我的MongoDB测试数据库中有以下文档:
db.a.find()
{[ {
"_id" : ObjectId("5113d680732fb764c44qweq"),
"Builds" : [
{
"level" : 1,
"rank" : 2
},
{
"level" : 3,
"rank" : 4
}
],
"abs" : [
{
"level" : 3,
"status" : 5
},
{
"level" : 3,
"status" : 4
}
]
}, {
"_id" : ObjectId("5113d680732fb764c4464fdf"),
"Builds" : [
{
"level" : 3,
"rank" : 5
},
{
"level" : 3,
"rank" : 4
}
],
"abs" : [
{
"level" : 3,
"status" : 5
},
{
"level" : 3,
"status" : 4
}
]
}
]}
我需要找到Builds level> = 2和< = 5并且abs status> = 5 它就像if(builds.leve> = 2&& builds.level< = 5&& abs.status> = 5&& abs.level> = 2) 多种条件 并需要采取一定的价值观 你可以帮助我吗?
答案 0 :(得分:1)
以下是适合您的示例。我对mongo cxx并不多,所以我不确定语法。
bsoncxx::builder::stream::document filter_builder;
filter_builder << "$or" << "Builds.level"
<< open_document << "$gte" << 1 << "$lte" << 5 << close_document
<< open_document << "abs.status" << "$gte" << 2 << "$lte" << 5
<< close_document << close_array;
auto cursor = db["your collection name"].find(filter_builder.view());
for (auto&& doc : cursor) {
std::cout << bsoncxx::to_json(doc) << std::endl;
}