Jackson在读取jersey-json生成的数据时发生UnrecognizedPropertyException

Question

我有这个带JAXB注释的类：

@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement
public class SomeClass {

    @XmlAttribute
    public String value;
}

基于此类，使用jersey-json（通过com.sun.jersey.api.json.JSONJAXBContext）生成JSON文档：

{
   "@value":"someValue"
}

请注意，泽西决定使用@value作为标记名称（而不仅仅是value），这可能是为了兑现@XmlAttribute注释。

现在的任务是使用jackson-json读取这个json文档并生成一个JAXB注释类的实例：

ObjectMapper mapper = new ObjectMapper();
JaxbAnnotationIntrospector introspector = new JaxbAnnotationIntrospector(mapper.getTypeFactory());
DeserializationConfig deserConfig = mapper.getDeserializationConfig().with(introspector);
mapper.setConfig(deserConfig);
SerializationConfig serConfig = mapper.getSerializationConfig().with(introspector);
mapper.setConfig(serConfig);
mapper.readValue(jsonFile, SomeClass.class);

此操作失败，但出现以下异常：

Caused by: com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "@value" (class test.jersey.vs.jackson.SomeClass), not marked as ignorable (one known property: "value"])
 at [Source: C:\Users\AppData\Local\Temp\junit5080915042527904512\json.txt; line: 1, column: 12] (through reference chain: test.jersey.vs.jackson.SomeClass["@value"])
    at com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException.from(UnrecognizedPropertyException.java:62)
    at com.fasterxml.jackson.databind.DeserializationContext.handleUnknownProperty(DeserializationContext.java:834)
    at com.fasterxml.jackson.databind.deser.std.StdDeserializer.handleUnknownProperty(StdDeserializer.java:1093)
    at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownProperty(BeanDeserializerBase.java:1477)
    at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownVanilla(BeanDeserializerBase.java:1455)
    at com.fasterxml.jackson.databind.deser.BeanDeserializer.vanillaDeserialize(BeanDeserializer.java:282)
    at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:140)
    at com.fasterxml.jackson.databind.ObjectMapper._readMapAndClose(ObjectMapper.java:3798)
    at com.fasterxml.jackson.databind.ObjectMapper.readValue(ObjectMapper.java:2740)

我现在的问题是，是否有办法告诉jackson将JSON文档中的@value标记与该类的value字段相关联。

我尝试指定PropertyNamingStrategy，但在反序列化期间从未调用过。

PropertyNamingStrategy pns = new PropertyNamingStrategy() {

    @Override
    public String nameForField(MapperConfig<?> config, AnnotatedField field, String defaultName) {

        if (field.hasAnnotation(XmlAttribute.class)) {
            if (defaultName.startsWith("@")) {
                return defaultName.substring(1);
            }
        }
        return super.nameForField(config, field, defaultName);
    }

};

DeserializationConfig deserConfig = mapper.getDeserializationConfig().with(introspector).with(pns);
mapper.setConfig(deserConfig);