Question

我正在处理一个刽子手脚本，但它没有正常工作。在这个例子中，我使用了＆＃34;好奇心＆＃34;作为猜测的词，因为它有三个＆＃34; i＆＃34; s。 F（或某些原因造型很奇怪，所以在块中）：

The desired output is "_ _ _ i _ _ i _ i _ _"
But I can only get to  "_ _ _ i _ _ i _ _ _ _"

这里是代码的主要部分：

def alter(output_word, guessed_letter, the_word):
    checkword = the_word
    #print ("outputword:",output_word)
    previous = 0
    fully_checked = False
    current_count = 0
    while fully_checked == False:
        global add_number
        checkword = checkword[previous:]
        add_number = previous + add_number

        #print ("..",checkword)
        if guessed_letter in checkword:

            current_count = current_count + 1
            print (">>>",current_count)
            the_index = (checkword.index(guessed_letter))+add_number
          #  print (output_word)
           #  print (the_index)
           # print (guessed_letter)
            output_word= output_word[:the_index-1] + guessed_letter + output_word[the_index:]

            previous = the_index+1  
        else:
            fully_checked = True
            checkword = the_word
            add_number = 0
    print (' '.join(output_word))
    checklist(current_count)  

def checklist(current_count):
    print ("checklist")
    print (current_count)
    global total_count
    total_count = total_count + current_count
    print ("total count is", total_count)

代码中的其他地方触发了这一切（the_word是好奇心，guessed_letter是i）：

if guessed_letter in the_word:
    alter(output_word, guessed_letter, the_word)

Answer 1

您将output_word的索引与切片checkword的索引混合在一起。

替换previous = the_index+1

带

previous = checkword.index(guessed_letter)+1

output_word= output_word[:the_index-1] + guessed_letter + output_word[the_index:]

中还有一个很小的切片事故

应该是

output_word= output_word[:the_index] + guessed_letter + output_word[the_index+1:]

输出：

_ _ _ i _ _ i _ i _ _

Answer 2

正如Derorrist指出的那样，你的代码逻辑存在一些缺陷，主要是你将output_word的索引与checkword的索引混为一谈。

我已修复了这些错误，并将您的代码压缩了一点。 add_number不需要是全局的，通常你应该避免使用可修改的全局变量，除非你真的需要它们，因为它们会破坏代码的模块性。

total_count = 0

def alter(output_word, guessed_letter, checkword):
    previous = add_number = current_count = 0
    while True:
        checkword = checkword[previous:]
        if guessed_letter in checkword:
            the_index = checkword.index(guessed_letter)
            offset = the_index + add_number
            print(">>>", current_count, the_index, offset)
            output_word= output_word[:offset] + guessed_letter + output_word[offset + 1:]
            previous = the_index + 1
            add_number += previous
            current_count += 1
        else:
            break

    print(' '.join(output_word))
    checklist(current_count) 
    return output_word

def checklist(current_count):
    global total_count

    print("checklist")
    print(current_count)
    total_count += current_count
    print("total count is", total_count, end='\n\n')

# test

the_word = "curiosities"
output_word = "_" * len(the_word)
print(' '.join(output_word))

for guessed_letter in 'cisotrue':
    output_word = alter(output_word, guessed_letter, the_word)

<强>输出

_ _ _ _ _ _ _ _ _ _ _
>>> 0 0 0
c _ _ _ _ _ _ _ _ _ _
checklist
1
total count is 1

>>> 0 3 3
>>> 1 2 6
>>> 2 1 8
c _ _ i _ _ i _ i _ _
checklist
3
total count is 4

>>> 0 5 5
>>> 1 4 10
c _ _ i _ s i _ i _ s
checklist
2
total count is 6

>>> 0 4 4
c _ _ i o s i _ i _ s
checklist
1
total count is 7

>>> 0 7 7
c _ _ i o s i t i _ s
checklist
1
total count is 8

>>> 0 2 2
c _ r i o s i t i _ s
checklist
1
total count is 9

>>> 0 1 1
c u r i o s i t i _ s
checklist
1
total count is 10

>>> 0 9 9
c u r i o s i t i e s
checklist
1
total count is 11

FWIW，有更简单的方法可以提高效率。例如，here是我前几天写的一对。

程序/循环仅部分工作

2 个答案: