Question

我有一个看起来像这样的数组：

Array ( 
[0] => Array ( 
    [Time] => 00 
    [Activity] => Surfing 
    ) 
[1] => Array ( 
    [Time] => 00 
    [Activity] => Surfing 
    ) 
[2] => Array ( 
    [Time] => 00 
    [Activity] => Kayaking 
    ) 
[3] => Array ( 
    [Time] => 15 
    [Activity] => Surfing 
    ) 
)

但我正在努力以正确的格式获得我需要的计数。基本上我希望实现的是每个'时间'内每个'活动'的计数。所以例如我想输出这样的东西：

Time:00 - Surfing 2; Kayaking 1
Time:15 - Surfing 1; Swimming 2
Time:45 - Surfing 1

等

我不确定我是否应该关注计数函数或者在foreach中进行预测？但它让我难过。提前谢谢。

Answer 1

我的尝试似乎有效：

$array = array(
    array("time"=>"00", "Activity"=>"Surfing"), 
    array("time"=>"00", "Activity"=>"Surfing"), 
    array("time"=>"00", "Activity"=>"Kayaking"), 
    array("time"=>"15", "Activity"=>"Surfing")
    );

$sortedArr = array();

/* first we need to sort the array so that we have a new array that is formatted with the time value as the key */

foreach($array as $arr) {

    $timeVal      = $arr['time'];
    $activityName = $arr['Activity'];

    /* if there is a time and activity key already set then we'll increment the count. Otherwise, we'll set it as 1 */

    if(isset($sortedArr[$timeVal][$activityName])) {
        $sortedArr[$timeVal][$activityName]++;
    } else {
        $sortedArr[$timeVal][$activityName] = 1;
    }
}

/* now we've re-ordered things, we'll build the output and then echo it out */

$output = '';
foreach($sortedArr as $key=>$vals) {
    $output.= 'Time:'.$key.' - ';

    foreach($vals as $activityName=>$activityCount) {
        $output .= $activityName.' '.$activityCount.';'.PHP_EOL;
    }
}

echo $output;

Answer 2

$new_array = array();
foreach ($array_list as $key => $val)
{
     if(isset($new_array[$val[$time]][$val['Activity']]))
     {
         $new_array[$val[$time]][$val['Activity']] += 1;
     }
     else
     {
         $new_array[$val[$time]][$val['Activity']] = 1;
     }
}

下一步你再次循环new_array，以便为你选择的每个唯一时间显示所有数组的新数组，或者如果您需要在新数据中进行比较，您可以直接访问新数组，如下所示

echo $new_array['00']['Surfing']

然后你将获得冲浪时间00的计数

祝你好运

Answer 3

您可以尝试：

$timings = [];
foreach ($array as $activity) {
    $timings[$activity['Activity']][] = $activity['Time'];
}

$surfing = array_sum($timings['Surfing']);

Answer 4

如果嵌套数组的结构不会改变你可以这样做：

$array = [
    [
        "Time" => "00",
        "Activity" => "Surfing"
    ],
    [
        "Time" => "00",
        "Activity" => "Surfing"
    ],
    [
        "Time" => "00",
        "Activity" => "Kayaking"
    ],
    [
        "Time" => "15",
        "Activity" => "Surfing"
    ]
];
$result = [];
foreach ($array as $key => $value) {
    $time = $value["Time"];
    $activity = $value["Activity"];
    if (!isset($result[$time])) {
        $result[$time] = [];
    }
    if (!isset($result[$time][$activity])) {
        $result[$time][$activity] = 0;
    }
    $result[$time][$activity]++;
}

结束print_r($result)返回此信息：

Array
(
[00] => Array
    (
        [Surfing] => 2
        [Kayaking] => 1
    )

[15] => Array
    (
        [Surfing] => 1
    )

)

Answer 5

我知道我迟到了，但这是我的代码。输出正是您想要的。

<?php

//mockup
$activities = array( 
                array( 
                        "Time"     => "00",
                        "Activity" => "Surfing",
                  ), 
                array( 
                        "Time"     => "00",
                        "Activity" => "Surfing",
                  ), 
                array( 
                        "Time"     => "00",
                        "Activity" => "Kayaking", 
                  ), 
                array( 
                        "Time"     => "15", 
                        "Activity" => "Surfing"
                    ), 
                array( 
                        "Time"     => "15", 
                        "Activity" => "Swimming"
                    ), 
                array( 
                        "Time"     => "15", 
                        "Activity" => "Swimming"
                    ), 
                array( 
                        "Time"     => "45", 
                        "Activity" => "Surfing"
                    )  
);

$reordered = array();

foreach($activities as $activity)
{
    foreach($activity as $key => $value)
    {
        //echo "$key => $value <br>";

        if($key=="Time")
        {
            $tmp_time = $value;
        }
        elseif($key=="Activity")
        {
            if(!isset($reordered[$tmp_time][$value]))
                $reordered[$tmp_time][$value]=1;
            else
            $reordered[$tmp_time][$value]++;
        }
    }
}


//var_dump($reordered);

$output='';

foreach($reordered as $key => $arr)
{
    $output.='Time:' . $key . ' - ';

    foreach($arr as $activityName=>$activityCount) 
    {
        $output.= $activityName.' '.$activityCount.'; ';
    }
    $output = rtrim($output,"; ");
    $output.=PHP_EOL;
}



echo $output;

/*

Time:00 - Surfing 2; Kayaking 1
Time:15 - Surfing 1; Swimming 2
Time:45 - Surfing 1

*/

php数组多维计数和foreach

5 个答案: