c.execute('''CREATE TABLE IF NOT EXISTS Electronic
(elem_no INTEGER PRIMARY KEY, Econf text)''')
lists = []
for i in range(1,5):
filenm = str(i)+".html"
print(filenm)
vals = []
with open(filenm, "r") as elfile:
for line in elfile:
mstr = "]Electron Configuration"
if mstr in line:
vals.insert(len(vals),"Hello")
print(len(vals))
lists.append(vals)
print(lists)
c.executemany("INSERT INTO Electronic VALUES(?)",lists)
conn.commit()
在每个[1-5] .html中,我有一行:
\grep "Electron Configuration" 1.html
[186]Electron Configuration 1s^1
现在,问题是,通过这种确切的设置,我收到错误:
1.html
1
2.html
1
3.html
1
4.html
1
[['Hello'], ['Hello'], ['Hello'], ['Hello']]
Traceback (most recent call last):
File "elem_parse.py", line 134, in <module>
c.executemany("INSERT INTO Electronic VALUES(?)",lists)
sqlite3.OperationalError: table Electronic has 2 columns but 1 values were supplied
因为我之前从未做过数据库,所以我尝试了:
c.executemany("INSERT INTO Electronic VALUES(?,?)",lists)
即。 增加VALUES中的字段,然后给出错误:
1.html
1
2.html
1
3.html
1
4.html
1
[['Hello'], ['Hello'], ['Hello'], ['Hello']]
Traceback (most recent call last):
File "elem_parse.py", line 134, in <module>
c.executemany("INSERT INTO Electronic VALUES(?,?)",lists)
sqlite3.ProgrammingError: Incorrect number of bindings supplied. The current statement uses 2, and there are 1 supplied.
由于我从未做过数据库,我正在关注Python-sqlite3 - Auto-increment of not null primary key?
但现在,我迷失了,无法弄清楚问题。
答案 0 :(得分:0)
使用两个参数标记(?
)时,还需要在lists
列表的每个元素中指定两个值。但是在这个应用程序中,你实际上并不想指定不同的值(或任何值)。
在表格中有两列,您必须为所有列提供值:
INSERT INTO Electronic VALUES (NULL, ?);
或指定要使用的列:
INSERT INTO Electronic(Econf) VALUES (?);