我在一个名为诊断:
的集合中有这样的文档pg_dump
处方对象数组中的药物 ID来自名为药物的单独集合,请参阅下面的示例文档:
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我正在尝试使用native node.js驱动程序创建一个mongodb查询,以获得如下结果:
{
"_id" : ObjectId("582d43d18ec3f432f3260682"),
"patientid" : ObjectId("582aacff3894c3afd7ad4677"),
"doctorid" : ObjectId("582a80c93894c3afd7ad4675"),
"medicalcondition" : "high fever, cough, runny nose.",
"diagnosis" : "Viral Flu",
"addmissiondate" : "2016-01-12",
"dischargedate" : "2016-01-16",
"bhtno" : "125",
"prescription" : [
{
"drug" : ObjectId("58345e0e996d340bd8126149"),
"instructions" : "Take 2 daily, after meals."
},
{
"drug" : ObjectId("5836bc0b291918eb42966320"),
"instructions" : "Take 1 daily, after meals."
}
]
}
非常感谢任何有关如何处理类似结果的建议,谢谢。
答案 0 :(得分:7)
使用MongoDB 3.4.4及更新版
使用聚合框架, $lookup
运算符支持数组
db.diagnoses.aggregate([
{ "$addFields": {
"prescription": { "$ifNull" : [ "$prescription", [ ] ] }
} },
{ "$lookup": {
"from": "drugs",
"localField": "prescription.drug",
"foreignField": "_id",
"as": "prescription.drug"
} }
])
对于较旧的MongoDB版本:
您可以使用 $unwind
运算符和 $lookup
后续管道步骤创建首先展平prescription
数组的管道做一个"左外连接"关于"药物"采集。从"加入"对已创建的数组应用另一个 $unwind
操作领域。 $group
来自第一个管道的先前展平的文档,其中 $unwind
运算符为处方数组中的每个元素输出文档。
组装上述管道,运行以下聚合操作:
db.diagnoses.aggregate([
{
"$project": {
"patientid": 1,
"doctorid": 1,
"medicalcondition": 1,
"diagnosis": 1,
"addmissiondate": 1,
"dischargedate": 1,
"bhtno": 1,
"prescription": { "$ifNull" : [ "$prescription", [ ] ] }
}
},
{
"$unwind": {
"path": "$prescription",
"preserveNullAndEmptyArrays": true
}
},
{
"$lookup": {
"from": "drugs",
"localField": "prescription.drug",
"foreignField": "_id",
"as": "prescription.drug"
}
},
{ "$unwind": "$prescription.drug" },
{
"$group": {
"_id": "$_id",
"patientid" : { "$first": "$patientid" },
"doctorid" : { "$first": "$doctorid" },
"medicalcondition" : { "$first": "$medicalcondition" },
"diagnosis" : { "$first": "$diagnosis" },
"addmissiondate" : { "$first": "$addmissiondate" },
"dischargedate" : { "$first": "$dischargedate" },
"bhtno" : { "$first": "$bhtno" },
"prescription" : { "$push": "$prescription" }
}
}
])
示例输出
{
"_id" : ObjectId("582d43d18ec3f432f3260682"),
"patientid" : ObjectId("582aacff3894c3afd7ad4677"),
"doctorid" : ObjectId("582a80c93894c3afd7ad4675"),
"medicalcondition" : "high fever, cough, runny nose.",
"diagnosis" : "Viral Flu",
"addmissiondate" : "2016-01-12",
"dischargedate" : "2016-01-16",
"bhtno" : "125",
"prescription" : [
{
"drug" : {
"_id" : ObjectId("58345e0e996d340bd8126149"),
"genericname" : "Paracetamol Tab 500mg",
"type" : "X",
"isbrand" : false
},
"instructions" : "Take 2 daily, after meals."
},
{
"drug" : {
"_id" : ObjectId("5836bc0b291918eb42966320"),
"genericname" : "Paracetamol Tab 100mg",
"type" : "Y",
"isbrand" : false
},
"instructions" : "Take 1 daily, after meals."
}
]
}
答案 1 :(得分:1)
在MongoDB 3.6或更高版本中
似乎
$lookup
将覆盖原始数组,而不是合并它。
一个可行的解决方案(如果您愿意,可以采用一种解决方法)是创建一个不同的字段,
然后合并两个字段,如下所示:
db.diagnoses.aggregate([
{ "$lookup": {
"from": "drugs",
"localField": "prescription.drug",
"foreignField": "_id",
"as": "prescription_drug_info"
} },
{ "$addFields": {
"merged_drug_info": {
"$map": {
"input": "$prescription",
"in": {
"$mergeObjects": [
"$$this",
{ "$arrayElemAt": [
"$prescription_drug_info._id",
"$$this._id"
] }
]
}
}
}
} }
])
这将再添加两个字段和所需字段的名称
将为merged_drug_info
。然后,我们可以添加$project
阶段进行过滤
删除多余的字段,并$set
阶段重命名该字段:
...
{ "$set": { "prescription": "$merged_drug_info" } },
{ "$project": { "prescription_drug_info": 0, "merged_drug_info": 0 } }
...