Question

我一直在努力奋斗数小时。我的SQLite插入总是返回-1 ...

以下是我在一个文件中的主要活动的代码，该文件在另一个文件中调用我的db代码：

public void onCreate（Bundle savedInstanceState）{ super.onCreate（savedInstanceState）; 的setContentView（R.layout.main）;

    jobsdb = new NotifyJobsDBAdapter(this);
    jobsdb.open();

    currentjobid = 1;
    currentjob = new Job(currentjobid, "Starting Tele Num", "Starting Text Msg");
    currentjobid = jobsdb.insertJob(currentjob);
   // this last statement returns -1
}

这是我在另一个文件中的数据库适配器代码：

public class NotifyJobsDBAdapter {

private static final String DB_NAME = "notifyjobsdb";
private static final String DB_TABLE = "notifyjobs";
private static final int DB_VERSION = 1;
private final Context ctx;

// Database column names
private static final String JOB_ID = "jobid";
private static final String JOB_TELE = "contactnumber";
private static final String JOB_TEXT = "textmessage";

private SQLiteDatabase notifyjobsdb;
private NotifyJobsDatabaseHelper dbHelper;
private boolean openness;
private boolean err;
private boolean err0;
private int cnt;
private int i1;
private String s1;
private String s2;
private static String s3;
private int res;
private SQLiteException ex0;
private SQLiteException ex1;

private static class NotifyJobsDatabaseHelper extends SQLiteOpenHelper {

    private static final String DATABASE_CREATE = 
        "CREATE TABLE IF NOT EXISTS " + DB_TABLE +
        " (+ " + JOB_ID + "INTEGER PRIMARY KEY, " +
        JOB_TELE + "TEXT NOT NULL, " +
        JOB_TEXT + "TEXT NOT NULL);";

    private static final String DATABASE_UPGRADE = 
        "DROP TABLE IF EXISTS notifyjobs ";

    public NotifyJobsDatabaseHelper(Context _context) {
        super(_context, DB_NAME, null, DB_VERSION);
    }

    @Override
    public void onCreate(SQLiteDatabase db) {
        db.execSQL(DATABASE_CREATE);
    }

    @Override
    public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
        db.execSQL(DATABASE_UPGRADE);
                }

}

public NotifyJobsDBAdapter(Context _context) {
    this.ctx = _context;
}

public void open() { 
    dbHelper = new NotifyJobsDatabaseHelper(ctx);
    try { notifyjobsdb = dbHelper.getWritableDatabase();
    } catch(SQLiteException ex) {
        ex0 = ex;
    }

}  

public void close() {
    notifyjobsdb.close();
}

//这是我的问题方法

public int insertJob(Job _job) {
    ContentValues newJobValues = new ContentValues();
    newJobValues.put(JOB_ID, _job.getjobid());
    newJobValues.put(JOB_TELE, _job.gettelenum());
    newJobValues.put(JOB_TEXT, _job.gettextmsg());
    notifyjobsdb.beginTransaction();
    // res is always returned a -1
    try {
    res = (int) notifyjobsdb.insertOrThrow(DB_TABLE, null, newJobValues);
    } catch (SQLiteException ex) {
        ex1 = ex;
    }

    notifyjobsdb.setTransactionSuccessful(); 
    close();
    return res;

这里，res始终为-1，调试器将ex1的详细消息显示为

“没有这样的表：notifyjobs :,编译时：INSERT INTO notifyjobs（contactnumber，textmessage，jobid）VALUES（？，？，？）;

我将不胜感激任何帮助！

Answer 1

有必要为表“_id”命名主id字段，以便Android知道绑定表的id字段的位置。因此，我建议您尝试将ID列命名为“_id”而不是“jobid”。

另外，我建议不要在只进行一次操作的情况下使用事务（以后可以决定将多个插入包装到事务中）。

Answer 2

DATABASE_CREATE语句中存在错误，因此未创建表。这就是你收到错误信息的原因。尝试修复您的create语句（打开括号后删除加号）：

private static final String DATABASE_CREATE = 
    "CREATE TABLE IF NOT EXISTS " + DB_TABLE +
    " (" + JOB_ID + " INTEGER PRIMARY KEY, " +
    JOB_TELE + " TEXT NOT NULL, " +
    JOB_TEXT + " TEXT NOT NULL);";

Answer 3

您的create语句错误。这是正确的：

private static final String DATABASE_CREATE = 
"CREATE TABLE IF NOT EXISTS " + DB_TABLE +
" (" + JOB_ID + " INTEGER PRIMARY KEY, " +
JOB_TELE + " TEXT NOT NULL, " +
JOB_TEXT + " TEXT NOT NULL);";

如果您尝试插入与约束不匹配的行（例如，已存在的主键或JOB_TELE / JOB_TEXT列的空值），则会出现异常。
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Insert使用SQLite返回-1

3 个答案: