从另一个字符串列表中搜索和删除字符串

Question

您好我有以下2个列表，我想基本上获得第3个更新列表，如果列表中的任何字符串'错'出现在列表'old'中，它会过滤掉包含它的整个字符串行。即我希望更新的列表等同于“新”列表。

wrong = ['top up','national call']
old = ['Hi Whats with ','hola man top up','binga dingo','on a national call']
new = ['Hi Whats with', 'binga dingo']

Answer 1

您可以使用filter：

>>> list(filter(lambda x:not any(w in x for w in wrong), old))
['Hi Whats with ', 'binga dingo']

或者，list comprehension，

>>> [i for i in old if not any(x in i for x in wrong)]
['Hi Whats with ', 'binga dingo']

如果您对这些问题感到不舒服，请使用如下所示的简单的基于for循环的解决方案：

>>> result = []
>>> for i in old:
...     for x in wrong:
...         if x in i:
...             break
...     else: 
...         result.append(i)
... 
>>> result
['Hi Whats with ', 'binga dingo']

Answer 2

>>> wrong = ['top up','national call']
>>> old = ['Hi Whats with ','hola man top up','binga dingo','on a national call']
>>> [i for i in old if all(x not in i for x in wrong)]
['Hi Whats with ', 'binga dingo']
>>>