Question

我到目前为止编写的代码如下：

String fname = type + (i + 1) + "-" + ext;

String fname1 = type + (i + 2) + "-" + System.currentTimeMillis() + ext;

File file = new File(myDir, fname);

if (file.exists()) {

    //file.delete();

    continue;

} else {

    try {

        InputStream in = getResources().openRawResource(x);

        FileOutputStream outStream = new FileOutputStream(file);

        byte[] buff = new byte[1024];

        byte[] buff1 = new byte[1024];

        int read = 0;

        try {

            while ((read = in.read(buff)) > 0) {

            outStream.write(buff, 0, read);

            //I wanted to fasten up the process so i added the code below: I have tried multiple way to do the same


            //FileInputStream fi = new FileInputStream(myDir+File.separator+fname);

            File File1 = new File(Environment.getExternalStorageDirectory()+File.separator + 
            "Application"+File.separator + "/Images" + "Image1-.jpg");

            File File2 = new File(Environment.getExternalStorageDirectory()+File.separator + "Application"+File.separator + "/Images" + fname1);

            //String name = in1.getName();

            File newname = new File(fname1);

            File1.renameTo(newname);

            FileUtils.copyDirectory(File1, File2);

        } 

finally {

    in.close();

    outStream.close();

}

然而，这不起作用。任何人都可以就如何解决这个问题给我一些建议吗？

Answer 1

您可以通过此处读取目录中的图像 -

file = new File(Environment.getExternalStorageDirectory() + File.separator + "image.jpg");

调用copyBack（）函数并传递文件路径和名称

 String shiftedPath = copyBack(file.getAbsolutePath(),newName);

//函数用于复制和重命名

public String copyBack(String srcPath,String newName) {
//you can defined path of same directory as per your requirement, and just pass new  
            file = new File(Environment.getExternalStorageDirectory() + File.separator + "newName");
            file.mkdirs();
            try {
    //            File sd = Environment.getExternalStorageDirectory();
    //            File data = Environment.getDataDirectory();

                String sourceImagePath = srcPath;
                String destinationImagePath = file.getAbsolutePath();
                File source = new File(sourceImagePath);
                destination = new File(file, ".image");
                if (source.exists()) {
                    FileChannel src = new FileInputStream(source).getChannel();
                    FileChannel dst = new FileOutputStream(destination).getChannel();
                    dst.transferFrom(src, 0, src.size());
                    src.close();
                    dst.close();

                }
            } catch (Exception e) {
                e.printStackTrace();
            }

            return destination.getAbsolutePath();
        }

如何从Android手机目录中读取图像，重命名并复制回同一目录？

1 个答案: