Question

我的情况如下。我有一个表订单（OrderId，ItemId），我希望获得所有订单，其中ItemId 1和2即将来到simulataneoudsly

OrderId ItemId
1000      1
1001      2
1002      1
1002      2
1002      3
1003      1
1003      2
1004      4
1004      5
1005      3
1006      1
1006      3

根据上面的表数据和问题......我应该得到输出OrderId 1002和1003.

Answer 1

使用import tkinter as tk class Example(tk.Frame): def __init__(self, *args, **kwargs): tk.Frame.__init__(self, *args, **kwargs) self.labelLists = [] self.labelBLists = [] self.Label1 = tk.Label(self,text=str(1),bg="red") self.Label1.pack() self.Label1.bind("<Enter>", self.on_enter1) self.Label1.bind("<Leave>", self.on_leave1) self.Labela = tk.Label(self,text="",bg="blue") self.Labela.pack() self.Label2 = tk.Label(self,text=str(2),bg="red") self.Label2.pack() self.Label2.bind("<Enter>", self.on_enter2) self.Label2.bind("<Leave>", self.on_leave2) self.Labelb = tk.Label(self,text="",bg="blue") self.Labelb.pack() self.Label3 = tk.Label(self,text=str(3),bg="red") self.Label3.pack() self.Label3.bind("<Enter>", self.on_enter3) self.Label3.bind("<Leave>", self.on_leave3) self.Labelc = tk.Label(self,text="",bg="blue") self.Labelc.pack() def on_enter1(self, event): self.Labela.config(text=self.Label1.cget("text")) def on_leave1(self, enter): self.Labela.config(text="") def on_enter2(self, event): self.Labelb.config(text=self.Label2.cget("text")) def on_leave2(self, enter): self.Labelb.config(text="") def on_enter3(self, event): self.Labelc.config(text=self.Label3.cget("text")) def on_leave3(self, enter): self.Labelc.config(text="") if __name__ == "__main__": root = tk.Tk() Example(root).pack(side="top", fill="both", expand="true") root.mainloop()和COUNT：

HAVING

如果SELECT OrderId FROM Orders WHERE ItemId IN(1, 2) GROUP BY OrderId HAVING COUNT(ItemId) = 2中允许重复ItemId，请使用：

OrderId

ONLINE DEMO

Answer 2

使用嵌套查询的另一个选项是：

SELECT orderId
FROM ORDERS o
WHERE o.itemId = 1
AND EXISTS (SELECT 'X'
              FROM ORDERS o1
             WHERE o1.orderId = o.orderId
               AND o1.itemId = 2);

ONLINE DEMO

同时获取ItemId 1和2的所有订单

2 个答案: