Question

这是我到目前为止所做的：

   import java.util.Scanner;

   public class ReverseNumber {

      public static void main(String args[])
      {
         int n, reverse = 0;

         System.out.println("Enter an integer: ");
         Scanner in = new Scanner(System.in);
         n = in.nextInt();

         while( n != 0 )
         {
             reverse = reverse * 10;
             reverse = reverse + n%10;
             n = n/10;
         }

         System.out.println(" in reverse order is "+reverse);
      }
   }

如果用户输入为123，那么它打印的内容，现在的样式是：

输入一个整数：

以相反的顺序是321

我需要知道要把它放在＆＃39;前面的地方，以相反的顺序打印123是＆＃39;言。

Answer 1

在更改输入值时，需要将其存储在不同的变量中并更改Sys out语句以添加实际值，例如：

.toggle()

Answer 2

我会这样做

 public static void main(String[] args) {
                int n, reverse = 0;
                System.out.println("Enter an integer: ");
                Scanner in = new Scanner(System.in);
                n = in.nextInt();
                int number = n;
                System.out.println(n);
                while( n != 0 )
                {
                    reverse = reverse * 10;
                    reverse = reverse + n%10;
                    n = n/10;
                }
                System.out.println(number+" in reverse order is "+reverse);
        }

Answer 3

如果要同时初始化多个变量，请使用两个不同的行。

由于您要更改n，请创建一个可以使用的副本。

import java.util.Scanner;

class Main {
  public static void main(String args[])
  {
     int n, reverse, initialNumber;
     n = reverse = initialNumber = 0;

     System.out.print("Enter an integer:");
     Scanner in = new Scanner(System.in);
     n = in.nextInt();
     initialNumber = n;

     while( n != 0 )
     {
         reverse = reverse * 10;
         reverse = reverse + n%10;
         n = n/10;
     }

     System.out.println(initialNumber + " in reverse order is " + reverse);
  }
}

试试here!

这个相反的订单我错过了什么？

3 个答案: