我在alertdialog中显示复选框。当用户单击OK时,toast应该像你选择了PHP,Java,JSON一样。现在,它显示ID。我怎样才能获得价值?
Dialog dialog;
final String[] items = {" Objective C", " JAVA", " JSON", " C#", "PHP"};
final ArrayList itemsSelected = new ArrayList();
AlertDialog.Builder builder = new AlertDialog.Builder(this);
builder.setTitle("Select Languages you know : ");
builder.setMultiChoiceItems(items, null,
new DialogInterface.OnMultiChoiceClickListener() {
@Override
public void onClick(DialogInterface dialog, int selectedItemId,
boolean isSelected) {
if (isSelected) {
itemsSelected.add(selectedItemId);
} else if (itemsSelected.contains(selectedItemId)) {
itemsSelected.remove(Integer.valueOf(selectedItemId));
}
}
})
.setPositiveButton("Done!", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int id) {
//Your logic when OK button is clicked
Toast.makeText(MainActivity.this,"You've selected "+itemsSelected,Toast.LENGTH_SHORT).show();
}
})
.setNegativeButton("Cancel", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int id) {
}
});
dialog = builder.create();
dialog.show();
[更新]我找到了解决方案,但似乎并不理想。现在它的工作是添加以下代码。
String one="";
String two="";
String three="";
String four="";
String zero="";
if (s.contains("0" ))
{
zero="Obj C ";
}
if (s.contains("1"))
{
one="JAVA ";
} if (s.contains("2"))
{
two="JSON ";
} if (s.contains("3"))
{
three="C# ";
} if (s.contains("4"))
{
four="PHP ";
}
答案 0 :(得分:0)
这部分代码
new DialogInterface.OnMultiChoiceClickListener() {
@Override
public void onClick(DialogInterface dialog, int selectedItemId,
boolean isSelected) {
if (isSelected) {
**itemsSelected.add(selectedItemId);**
} else if (itemsSelected.contains(selectedItemId)) {
itemsSelected.add(selectedItemId)只是将id添加到你的arraylist中。您不希望添加ID。由于您希望添加精确值,因此您可以简单地使用itemsSelected.add(items [selectedItemId])之类的内容,因为items数组包含您需要显示的值。当你在arraylist中放入正确的值时,你可以使用itemsSelected.toString()或其他东西显示你的吐司。您还需要处理所有其他检查。