Python ValueError错误消息

Question

如何在捕获之后实际打印出ValueError的消息？

Answer 1

try:
    ...
except ValueError as e:
    print(e)

Answer 2

Python 3需要在打印之前将异常强制转换为字符串：

try:
    ...
except ValueError as error:
    print(str(error))

Answer 3

另一种使用 logging

的方法

import logging
try:
    int("dog")
except Exception as e:
    logging.warning(e)
    logging.error(e)

给予

WARNING:root:invalid literal for int() with base 10: 'dog'
ERROR:root:invalid literal for int() with base 10: 'dog'

[Program finished]

只需输入异常即可，

invalid literal for int() with base 10: 'dog'

[Program finished]

取决于你想如何处理输出