我的任务是在抽奖中抽出一个随机数作为一张票。然后我需要猜猜它是多少。这种猜测操作需要完成100次。我不知道我的程序是否运行良好,因为每次我在屏幕上打印机会时,它都会在每一步中给出正确答案。我有全局声明的步骤变量,所以可能这就是为什么它始终是相同的。但是机会呢?
#include<stdio.h>
#include<time.h>
int fchance(int min, int max, int ticket);
int steps = 0;
int main(void) {
int ticket, chance;
int i;
int stepsInTry = 0;
int stepsAverage;
srand(time(NULL));
// rand() % (max - min) + min;
for (i = 0; i < 100; i++) {
ticket = rand() % 100 + 1;
printf("Your ticket: %d ", ticket);
steps = 1;
chance = rand() % 100 + 1;
printf("\nChance: %d", chance);
while (ticket != chance) {
if (chance < ticket) {
chance = ftraf(chance, 100, ticket);
printf("\nChance: %d, step: %d", chance, steps);
}
if (chance > ticket) {
chance = ftraf(1, chance, ticket);
printf("\nChance: %d, step: %d", chance, steps);
}
}
printf("\nOperation nr: %d - number of steps: %d \n", i+1, steps);
stepsInTry += steps;
system("PAUSE");
}
stepsAverage = stepsInTry / 100;
printf("\n\nAverage of steps: %d ", stepsAverage);
system("PAUSE");
return 0;
}
int fchance(int min, int max, int ticket) {
steps++;
int chance;
chance = rand() % (max - min) + min;
if (chance < ticket) {
chance = fchance(chance, 100, ticket);
printf("\nChance: %d, step: %d", chance, steps);
}
if (chance > ticket) {
chance = fchance(1, chance, ticket);
printf("\nChance: %d, step: %d", chance, steps);
}
return chance;
}
输出示例:
Your ticket: 65
Chance: 38
Chance: 65, step: 11
Chance: 65, step: 11
Chance: 65, step: 11
Chance: 65, step: 11
Chance: 65, step: 11
Chance: 65, step: 11
Chance: 65, step: 11
Chance: 65, step: 11
Chance: 65, step: 11
Chance: 65, step: 11
Operation nr: - numbers of steps: 11
@EDIT
对于代码中的混乱感到抱歉。将变量名称从我的母语更改为英语。
答案 0 :(得分:0)
fchance
函数在打印任何内容之前找到ticket
的值。我建议在printf
语句之后移动chance = rand()...
语句。
- β