如何在Mysql中显示顶级值作为顶部

Question

我想显示大学名称和应用程序数量来自每个大学，并显示大多数应用程序获得大学作为MySQL查询的第一个位置？

这是示例表，iter()是大学名称，clg列必须是application_name，最高值字段必须显示在顶部

我的结果必须是这样的......

Answer 1

试试这个，

{
  "rules": {
    ".read": "auth != null",
    ".write": "auth != null"
  }
}

Answer 2

我正在回答这个问题，因为public final class CaseInsensitive2 { private CaseInsensitive2() { } private static final Type mapStringObjectType = new TypeToken<Map<String, Object>>() { }.getType(); public static void main(final String... args) { final Gson originalGson = new Gson(); final Gson gson = decorateGson(originalGson); @SuppressWarnings("unchecked") final Map<String, Object> map1 = gson.fromJson(JSON_1, mapStringObjectType); @SuppressWarnings("unchecked") final Map<String, Object> map2 = gson.fromJson(JSON_2, mapStringObjectType); out.println(isTupleValid(map1)); out.println(isTupleValid(map2)); } private static boolean isTupleValid(final Map<String, Object> map) { return map != null && map.containsKey(TYPE) && map.containsKey(XID) && map.containsKey(CTP) && map.get(TYPE).equals("pageview"); } private static Gson decorateGson(final Gson originalGson) { @SuppressWarnings({ "unchecked", "rawtypes" }) final TypeAdapter<Map<String, Object>> adapter = (TypeAdapter) originalGson.getAdapter(Map.class); final JsonDeserializer<Map<String, Object>> typeAdapter = (json, type, context) -> normalizeMap(adapter.fromJsonTree(json)); return new GsonBuilder() .registerTypeAdapter(mapStringObjectType, typeAdapter) .create(); } } 中的列应该是唯一的，特别是在select子句中引用它们时。查询看起来应该更像：

order by