Question

是否有更有效的方式加入元组？既然我的rx给了我一个元组？此外，c是＆＃39; 7：30＆＃39; ＆＃39; AM＆＃39;最后，我需要＆＃39; 30 AM＆＃39;

import re

rx = r"(?i)\b(\d{1,2}:\d{2})(?:-\d{1,2}:\d{2})?(\s*[pa]m)\b"
s = "ankkjdf 7:30-8:30 AM dds "

matches = re.findall(rx, s)

m=str(matches)

a =''.join(m[2:8])
b= ''.join(m[9:15])

c = "".join(a + b)

print(c)

Answer 1

>>> import re
>>> rx = r"(?i)\b(\d{1,2}:\d{2})(?:-\d{1,2}:\d{2})?(\s*[pa]m)\b"
>>> s = "ankkjdf 7:30-8:30 AM dds "
>>> matches = re.findall(rx, s)
>>> matches
[('7:30', ' AM')]
>>> [ "".join(x) for x in matches]
['7:30 AM']
>>>

或

>>> "".join(matches[0])
'7:30 AM'
>>>

或直接来自

>>> [ "".join(x) for x in re.findall(rx, s)]
['7:30 AM']
>>> "".join( re.findall(rx, s)[0] )
'7:30 AM'
>>>

没有理由做m=str(matches)，只是把你得到的东西融合在一起......

使用最新的例子

>>> test="Join us for a guided tour of the Campus given by Admissions staff. The tour will take place from 1:15-2:00 PM EST and leaves from the Admissions Office."
>>> [ "".join(x) for x in re.findall(rx, test)]
['1:15 PM']
>>> "".join( re.findall(rx, test)[0] )
'1:15 PM'
>>>

更高效的加入元组的方法？

1 个答案: