Python Difflib - 如何获得PHP Diff Class格式的差异序列

时间:2016-12-03 22:29:25

标签: php python perl difflib

我正在阅读python difflib文档。根据difflib.differ输出是:

代码含义 ' - '对序列1唯一的行 '+'行对序列2是唯一的 ''两个序列共有的线 “? '输入序列中不存在行

我也在stackoverflow上阅读这个问题 Python Difflib - How to Get SDiff Sequences with "Change" Op但无法在Sнаđошƒаӽ的答案中添加评论。

我不知道Perl的Sdiff是什么,但我需要调整这个功能:

def sdiffer(s1, s2):
    differ = difflib.Differ()
    diffs = list(differ.compare(s1, s2))

    i = 0
    sdiffs = []
    length = len(diffs)
    while i < length:
        line = diffs[i][2:]
        if diffs[i].startswith('  '):
            sdiffs.append(('u', line))

        elif diffs[i].startswith('+ '):
            sdiffs.append(('+', line))

        elif diffs[i].startswith('- '):
            if i+1 < length and diffs[i+1].startswith('? '): # then diffs[i+2] starts with ('+ '), obviously
                sdiffs.append(('c', line))
                i += 3 if i + 3 < length and diffs[i + 3].startswith('? ') else 2

            elif diffs[i+1].startswith('+ ') and i+2<length and diffs[i+2].startswith('? '):
                sdiffs.append(('c', line))
                i += 2
            else:
                sdiffs.append(('-', line))
        i += 1
    return sdiffs

就像PHP Diff Class

上面的函数我试过,它返回UNCHANGE,ADDED和DELETED的值。 DELETED更复杂,有4种不同的情况:

案例1 :通过插入一些字符来修改该行

- The good bad
+ The good the bad
?          ++++

案例2 :通过删除一些字符来修改该行

- The good the bad
?          ----
+ The good bad

案例3 :通过删除和插入和/或替换某些字符来修改该行:

- The good the bad and ugly
?      ^^ ----
+ The g00d bad and the ugly
?      ^^          ++++

案例4 :该行已删除

- The good the bad and the ugly
+ Our ratio is less than 0.75!

我不知道如何在此代码中进行调整

elif diffs[i].startswith('- '):
        if i+1 < length and diffs[i+1].startswith('? '): # then diffs[i+2] starts with ('+ '), obviously
            sdiffs.append(('c', line))
            i += 3 if i + 3 < length and diffs[i + 3].startswith('? ') else 2

        elif diffs[i+1].startswith('+ ') and i+2<length and diffs[i+2].startswith('? '):
            sdiffs.append(('c', line))
            i += 2
        else:
            sdiffs.append(('-', line))

跳过'?'线。我只想在没有插入新行的情况下追加( - ),如果调用插入新行,则追加(+)。

1 个答案:

答案 0 :(得分:0)

我想我已经完成了我想要的PHP Diff输出。

def sdiffer(s1, s2):
    differ = difflib.Differ()
    diffs = list(differ.compare(s1, s2))

    i = 0
    sdiffs = []
    length = len(diffs)
    sequence = 0
    while i < length:
        line = diffs[i][2:]
        if diffs[i].startswith('  '):
            sequence +=1
            sdiffs.append((sequence,'u', line))

        elif diffs[i].startswith('+ '):
            sequence +=1
            sdiffs.append((sequence,'+', line))

        elif diffs[i].startswith('- '):
            sequence +=1
            sdiffs.append((sequence,'-',diffs[i][2:]))
            if i+1 < length and diffs[i+1].startswith('? '):
                if diffs[i+3].startswith('?') and i+3 < length : # case 3
                    sequence +=1
                    sdiffs.append((sequence,'+',diffs[i+2][2:]))
                    i+=3
                elif diffs[i+2].startswith('?') and i+2 < length: # case 2
                    sequence +=1
                    sdiffs.append((sequence,'+',diffs[i+2][2:]))
                    i+=2
            elif diffs[i+1].startswith('+ ') and i+2<length and diffs[i+2].startswith('? '): # case 1
                sequence +=1
                sdiffs.append((sequence,'+', diffs[i+1][2:]))
                i += 2
            else: # the line is deleted and inserted new line # case 4
                sequence +=1
                sdiffs.append((sequence,'+', diffs[i+1][2:]))
                i+=1   
        i += 1
    return sdiffs