为新手问题道歉,但我对PHP比较陌生,想要做一些相当简单的事情...如果我有一系列的按键&价值观(梨):
$arrayOfPears = array(
"Green Anjou" => [ 7,
"plump",
"ripe",
"juicy",
"green"
],
"Bartlett" => [ 2,
"moderately plump",
"unripe",
"sweet",
"greeny-yellow"
],
"Comice" => [ 3,
"rather plump",
"ripe",
"blinding",
"deep-green"
],
"Plum" => [ 6,
"rotund",
"over-ripe",
"sweet",
"purple",
"not really a pear, as far as I'm aware"
]
);
我能够访问特定梨的值并将其用于比较操作。例如:
if($arrayofPears['Comice'][2] == "ripe") {
$nibble = true;
return $nibble;
}
返回真实的$nibble
。但是,我希望能够做的是首先检查数组中是否存在Comise
键,之前我尝试输入if语句并查明是否得到了是$nibble
。
那么......在承诺输入条件之前,我如何检查在这种情况下是否存在'Comice'?
答案 0 :(得分:0)
你可以试试这个:
if(array_key_exists("Comice",$arrayOfPear){
//Do the Loop
}
else{
//Don't enter the loop
}