Question

所以我有一个列表和一个for循环（仍然是初学者抱歉），我想要这个代码，但是更简单的方式，没有新的向后列表。 ^编辑

lyrics = [["First", "and a partride in a pear tree",], ["second", "2 things"], ["Third", "3 things"], ["Fourth", "4 things"], ["Fifth", "5 things"], ["Sixth", "six things"], ["Seven", "7 things"], ["Eigth", "8 things"], ["Nineth", "nine things"], ["tenth", "Ten things"], ["eleventh", "eleven things"], ["Twelveth", "twelve things"]]

backwards = []

for i in range(12):
    print("On the", lyrics[i][0], "my true love gave to me,               lyrics[i][1])
backwards.append(lyrics[i][1])
for each in backwards:
    print (each) #Forgot how i did it in the reverse order but i want this in a more simplified version to learn from.

PS：希望尽可能少的线（我能够在8行中完成，但至少需要3-4行）：/

Answer 1

您可以在此处使用range：

my_str = ['A', 'B', 'C']
for i, val in enumerate(my_str):
    print ' '.join(my_str[i::-1])

或者，在一行中：

print '\n'.join(' '.join(my_str[i::-1]) for i in range(len(my_str))

这两个都会打印出来：

A
B A
C B A

我不确定这是否符合要求。该结果基于：

我怎样才能这样做，所以A将被打印，然后是B和A，最后是C和B和A.

Python-需要帮助来简化我的代码

1 个答案: