Question

我的更新表单有问题。按下更新按钮时，它始终更新表格的顶行而不是您要更新的表格。使用jquery ajax sendForm函数在按下update时对div进行更新。它在添加该功能之前有效。尝试更新其他行也会将更改还原到顶行。

`
foreach ($pdo->query('
 SELECT *
  from SubPlaceViewer;
   ')as $row) {

      echo "<tr>";
    echo "<td>".$row['name']."</td>";
    echo "<td>".$row['placeName']."</td>";
    echo "<td>".$row['realName']."</td>";
    echo "<td>".$row['entID']."</td>";
    echo "<td>".$row['firstName']." ".$row['lastName']."</td>";
    echo "<td>".$row['length']."</td>";
    echo "<td>".$row['height']."</td>";
    echo "<td>".$row['fakesnow']."</td>";
    ?>

    <td>/* Changed form-id. Still doesnt d */
    <form id="changeSubPlace<?php echo $row['name']; ?>">
       <input type="hidden" name="name" value="<?php echo $row['name']; ?>">
    <select name='entID'>    
    <?php 
    foreach ($pdo->query('SELECT * FROM Ent') as $row) {
      echo '<option value="'.$row['entID'].'">';
      echo $row['firstName']." ".$row['lastName'];
      echo "</option>";
    }
    ?>
  </select>
  <button type="button" onclick="SendForm('subplace', 'subplace', 'changeSubPlace<?php echo $row['name']; ?>');">update</button>
</form>
    </td>
  </tr>
  <?php
}
?>   
</table>
</div>

<?php
if(isset($_POST['name'])){
  $sql = "call _newResponsabilitySubPlace (:_entID,:_name)";
  $stmt = $pdo->prepare($sql);
  $stmt->bindParam(":_entID", $_POST['entID'], PDO::PARAM_INT);
  $stmt->bindParam(":_name", $_POST['name'], PDO::PARAM_INT);
  $stmt->execute();
}    
?>`

功能：

function SendForm(page, go, form) {

$.ajax({
    url : 'includes/'+page+'.php', // där formulär inmatning hanteras.
    type: 'POST',
    data: $("#"+form).serialize(), // serializes formulärets element.

    success: function(data){
        MakeRequest(go);  // den div som ska laddas efter körning.
    }
});

}

PHP表单+选择UPDATE到MYSQL表不会更新行

0 个答案: