如何将结果集数据转换为我的对象。以下是数据格式

Question

我的数据就像结果集中的返回

[[{hostItemId=44, userId=1, title=This is the title 29 for skill(cleaning) for paid items..., description=This is the description 29 for skill ( cleaning) for paid items..., isFree=false, price=42.0, requestCount=2, categoryId=3, attachmentUrl=1478684543988image.jpg, currencySymbol=20B9, hostItemStatus=3, shareType=1}, {hostItemId=24, userId=1, title=This is title 15 for skill (spring chores)..., description=This is the description 15 for skill (spring chores)..., isFree=true, price=null, requestCount=2, categoryId=3, attachmentUrl=1478672337661image.jpg, currencySymbol=null, hostItemStatus=3, shareType=1}]]

Answer 1

您提供的Json数据是错误的。它会抛出一个错误。 Json数据的正确语法是var jsondata = [ [ { "hostItemId": 44, "userId": 1, "title": "This is the title 29 for skill(cleaning) for paid items...", "description": "This is the description 29 for skill ( cleaning) for paid items...", "isFree": false, "price": 42, "requestCount": 2, "categoryId": 3, "attachmentUrl": "1478684543988image.jpg", "currencySymbol": "20B9", "hostItemStatus": 3, "shareType": 1 }, { "hostItemId": 24, "userId": 1, "title": "This is title 15 for skill (spring chores)...", "description": "This is the description 15 for skill (spring chores)...", "isFree": true, "price": null, "requestCount": 2, "categoryId": 3, "attachmentUrl": "1478672337661image.jpg", "currencySymbol": null, "hostItemStatus": 3, "shareType": 1 } ] ]

之后，您可以将此json字符串解码为您的对象。

// Creating a JSONObject from a String 
JSONObject nodeRoot  = new JSONObject(jsondata); 

// Creating a sub-JSONObject from another JSONObject
JSONObject nodeStats = nodeRoot.getJSONObject("stats");