Question

在我的程序中，我有一个加号和减号按钮，可以增加或减少文本字段的数量。现在我要做的是在填写所有字段后打开一个新面板。我遇到的问题是，如果我只填写其中一个文本字段并单击验证按钮，即使其他文本字段为空，也会转到下一个面板。

    stage = primaryStage;

    pane = new BorderPane();
    pane.setStyle("-fx-background: #CEF6D8;");

    centerPane1 = new Pane();

    GridPane mainGrid = new GridPane();
    mainGrid.setPadding(new Insets(150, 0, 0, 100));
    mainGrid.setVgap(50);

    // ADULTS, CHILDREN AND INFANT GRID
    noPassGrid = new GridPane();
    noPassGrid.setHgap(10);

    plus = new Button("+");
    plus.setMinWidth(50);
    plus.setFont(Font.font("Verdana", 20));
    GridPane.setConstraints(plus, 1, 0);

    plus.setOnAction(e -> {
        plus(count);
        getArraySize();
    });

    count = new Label("1");
    count.setFont(Font.font("Verdana", 20));
    GridPane.setConstraints(count, 2, 0);

    minus = new Button("-");
    minus.setMinWidth(50);
    minus.setFont(Font.font("Verdana", 20));
    GridPane.setConstraints(minus, 3, 0);

    minus.setOnAction(e -> {
        minus(count);
            getArraySize();
    });


    noPassGrid.getChildren().addAll(plus, count, minus);

    GridPane.setConstraints(noPassGrid, 0, 2);

    mainGrid.getChildren().addAll(noPassGrid);


    search = new Button("SEARCH");
    search.setPrefSize(300, 100);
    search.setFont(new Font("Verdana", 30));
    grid = new GridPane();
    grid.setPadding(new Insets(150, 0, 0, 450));
    grid.setVgap(20);
    grid.setHgap(20);

    test = new Label();
    test.setFont(Font.font("Verdana", 20));
    test.setLayoutX(500);
    test.setLayoutX(100);



    search.setOnAction(e -> {

        for(int i=0; i<arrayLength; i++) {
            passName[i] = new TextField();
            passName[i].setFont(Font.font("Verdana", 20));
            passName[i].setPromptText("Enter Name");
            GridPane.setConstraints(passName[i], 2, i);

            grid.getChildren().addAll(passName[i]);
        }
    });

    verify = new Button("VERIFY");
    verify.setPrefSize(300, 100);
    verify.setFont(new Font("Verdana", 30));

    verify.setOnAction(e -> {
        for(int i=0; i<arrayLength; i++) {
            if(passName[i].getText().equals("")) {
                test.setText("INCORRECT");
            }
            else {
                center2 = new Pane();
                pane.setCenter(center2);
            }
        }
    });


    centerPane1.getChildren().addAll(mainGrid, grid, test);
    pane.setCenter(centerPane1);

    bottom1 = new AnchorPane(verify, search);
    bottom1.setPadding(new Insets(0, 0, 100, 0));
    AnchorPane.setRightAnchor(search, 150.0);
    AnchorPane.setLeftAnchor(verify, 150.0);
    pane.setBottom(bottom1);

    scene = new Scene(pane, 1200, 600);
    stage.setScene(scene);
    stage.show();

}


public void getArraySize() {
    arrayLength = counter;
    passName = new TextField[arrayLength];
}

public void plus(Label l) {
    if(counter < 8) {
        counter++;
        l.setText("" + counter);
    }
}

public void minus(Label l) {
    if(counter > 1) {
        counter--;
        l.setText("" + counter);
    }
}

您能否告诉我我的代码有什么问题？

谢谢，马可

Answer 1

问题在于验证按钮的逻辑，如果至少填充了一个文本字段，则按钮将使窗格显示，另一方面，只有当所有文本字段都填满时，您才想使窗格显示你应该做这样的事情：

verify.setOnAction(e -> {
    boolean valid = true; // Variable to store whether the inputs are filled
    for(int i=0; i<arrayLength; i++) {
        if(passName[i].getText().equals("")) {
            valid = false;
        }
    }

    if(valid) {
        center2 = new Pane();
        pane.setCenter(center2);
    } else {
        test.setText("INCORRECT");
    }
});

验证javaFX中的TextField数组

1 个答案: