将动态值传递给php并获取日期

Question

Button.Dock = Fill

需要将此值传递给php中的var dt = 6; var dtyp = M; 以获取6个月后的日期strtotime需要将当天日期添加6天，if dtyp = D需要将当前日期添加6年。

if dtyp = Y

<?php echo date("d/m/Y", strtotime("+6 days"));?> $.each(data.response.duration,function(a,b){ var dt = b.exp_dur; var dtyp = b.exp_type; $('.after_dat').val('<?php echo date("d/m/Y", strtotime("+.'dt'. days"));?>') }); 和dt将从db动态获取。

Answer 1

                             if(b.exp_type === 'D'){
                                $('.after_dat').val('');
                                var date = new Date();
                                futr =  parseInt(b.exp_dur)
                                date.setDate(date.getDate() +futr);
                                var dateMsg = date.getDate()+'/'+ (date.getMonth()+1) +'/'+date.getFullYear();
                                // alert(dateMsg);
                                $('.after_dat').val(dateMsg);
                            }
                            if(b.exp_type === 'M'){
                                $('.after_dat').val('');
                                futr =  parseInt(b.exp_dur)
                                var jan312009 = new Date();
                                var eightMonthsFromJan312009 = new Date(new Date(jan312009).setMonth(jan312009.getMonth()+futr));
                                var dateMsg = eightMonthsFromJan312009.getDate()+'/'+ (eightMonthsFromJan312009.getMonth()+1) +'/'+eightMonthsFromJan312009.getFullYear();
                                $('.after_dat').val(dateMsg);

                            }
                            if(b.exp_type === 'Y'){
                                $('.after_dat').val('');
                                futr =  parseInt(b.exp_dur)
                                var jan312009 = new Date();
                                var eightMonthsFromJan312009 = new Date(new Date(jan312009).setFullYear(jan312009.getFullYear()+futr));
                                var dateMsg = eightMonthsFromJan312009.getDate()+'/'+ (eightMonthsFromJan312009.getMonth()+1) +'/'+eightMonthsFromJan312009.getFullYear();
                                $('.after_dat').val(dateMsg);

                            }