Question

我必须从一个范围中获取整数的用户输入，将其转换为二进制，并用二进制填充3x3数组。唯一的问题是，我的代码给我的输出只依赖于该二进制的前3个数字（即所有行的010001101 = 010）。

import java.util.Scanner;
public class HW11P02 { 

    public static void main(String[] args) {
        Scanner in = new Scanner (System.in);
        System.out.print("Enter a number between 0 and 511: ");
        int n = in.nextInt();


        String binary = Integer.toBinaryString(n);
        binary = binary.format("%09d", Integer.parseInt(binary));
        System.out.println(binary);

        listArray(binary);


    };

    public static String[][] listArray(String binary) {
        String[][] array = new String[3][3];

        char ch = ' ';
        String value = "";

        for (int i = 0; i < 3; i++) {
            for (int n = 0; n < 3; n++) {
                ch = binary.charAt(n);
                value = Character.toString(ch);
                array[i][n] = value;
                System.out.print(array[i][n] + " ");
            }
            System.out.println();
        }



        return array;
    }
};

Answer 1

我认为这将提供您可能真正想要的输出。

import java.util.Scanner;

公共类HW11P02 {

public static void main(String[] args)
{
    Scanner in = new Scanner (System.in);
    System.out.print("Enter a number between 0 and 511: ");
    int n = in.nextInt();

    String binary = Integer.toBinaryString(n);
    binary = binary.format("%09d", Integer.parseInt(binary));
    System.out.println(binary);

    int result[][]=new int[3][3];
    int position=0;
    for (int i = 0; i < result.length; i++)
    {
        for (int j = 0; j < result.length; j++)
        {
            result[i][j]=binary.charAt(position++)-'0';
            System.out.print(result[i][j]+" ");
        }
        System.out.println();
    }


}

}

使用用户输入填充2D数组（整数到二进制）

1 个答案: