Question

如何访问＆＃34;参数＆＃34;网址中的字词：

operations_product_search/?q=parameter

这里：

类ASearchView（ListView）：

...

def get_queryset(self, **kwargs):
    q = self.kwargs["q"]  <--- This is not working

Answer 1

应该是self.request.GET['q']。

Answer 2

我使用query_params

获取查询参数

public class GluonApplication extends MobileApplication {

@Override
public void init() {

    addViewFactory(HOME_VIEW, () ->
    {

        TextField txtFloating = new TextField();
        txtFloating.setFloatText("floating");

        TextField txtNonFloating = new TextField();
        txtNonFloating.setPromptText("non floating");

        Button btnClear = new Button("clear text");
        btnClear.setOnAction(e -> {
            txtFloating.setText(null);
            txtNonFloating.setText(null);
        });

        VBox boxContent = new VBox(20,txtNonFloating, txtFloating, btnClear);
        boxContent.setAlignment(Pos.CENTER);

        View view = new View(boxContent) {

            @Override
            protected void updateAppBar(AppBar appBar) {
                appBar.setTitleText("Home");
            }

        };

        return view;
    });

}

Answer 3

如果您使用get()，则可以通过提供备用值（此处为None）来避免URL中不存在'q ='的异常：

 def get_queryset(self):
     q = self.request.GET.get('q', None)

Django GET？q =＆＃34;参数＆＃34;在get_queryset基于类的视图中

3 个答案: