Question

尝试为多个子任务制作api。我有任务模型，可以将另一个任务作为父项：

class Task(models.Model):
    parent_task = models.ForeignKey("Task", null=True, blank=True)
    name = models.CharField(max_length=64)

    def __unicode__ (self):
        return self.name

现在我正试图制作tastypie资源：

class TaskResource(ModelResource):
    parent_task = fields.ForeignKey(TaskResource, 'parent_task', full=False) <-- ERROR HERE

    class Meta:
        queryset = Task.objects.all()
        resource_name = 'task'
        list_allowed_methods = ['get', 'put', 'post', 'delete']
        include_resource_uri = False

    def dehydrate(self, bundle, for_list=False):
        bundle.data["subtasks"] = "how?" <-- HOW??
        return bundle

感谢您的时间。

P.S。我需要这样的东西：

[
    {
        "id": 1,
        "name": "Task 1",
        "subtasks": [
            {
                "id": 1,
                "name": "Task 1",
                "subtasks": [...]
            }
        ]
    },
    {
        "id": 2,
        "name": "Task 2",
        "subtasks": "how?"
    }
]

Answer 1

几乎是Including child resources in a Django Tastypie API的副本，但不完全是。

所以你的第一个问题是你指定与自我错误的关系。它应该只是self：
```
parent_task = fields.ForeignKey('self', 'parent_task', null=True, full=False)
```
其次，请注意null=True - 父级可以是null。
最后，您只需要添加另一个关系字段并询问完整的详细信息
```
subtasks = fields.ToManyField('self', 'task_set', full=True)
```
task_set是related_name字段的Task.parent_task。

结果代码是：

class TaskResource(ModelResource):
    parent_task = fields.ForeignKey('self', 'parent_task', null=True, full=False)
    subtasks = fields.ToManyField('self', 'subtasks', full=True)

    class Meta:
        queryset = Task.objects.all()
        resource_name = 'task'
        list_allowed_methods = ['get', 'put', 'post', 'delete']
        include_resource_uri = False

结果：

{
    "meta": {
        "previous": null, 
        "total_count": 3,  
        "offset": 0,  
        "limit": 20, 
        "next": null
    },  
    "objects": [
        {
            "parent_task": null, 
            "subtasks": [
                {
                    "parent_task": "/api/v1/task/1/", 
                    "subtasks": [], 
                    "id": 2,  
                    "name": "Root's Child 1"
                },
                {
                    "parent_task": "/api/v1/task/1/", 
                    "subtasks": [], 
                    "id": 3,  
                    "name": "Root's Child 2"
                }
            ],
            "id": 1,  
            "name": "Root Task"
        },
        {
            "parent_task": "/api/v1/task/1/", 
            "subtasks": [], 
            "id": 2,  
            "name": "Root's Child 1"
        },
        {
            "parent_task": "/api/v1/task/1/", 
            "subtasks": [], 
            "id": 3,  
            "name": "Root's Child 2"
        }
    ]   
}

Django-Tastypie自己的孩子

1 个答案: