我的例外来源是什么?

时间:2016-12-02 17:31:40

标签: python windows

我有一个在Linux上运行良好的Python 3脚本。当我在Windows下运行它时,每次尝试播放声音时都会得到以下回溯:

Traceback (most recent call last):
  File "<string>", line 1, in <module>
  File "C:\Program Files (x86)\Python35-32\lib\multiprocessing\spawn.py", line 106, in spawn_main
    exitcode = _main(fd)
  File "C:\Program Files (x86)\Python35-32\lib\multiprocessing\spawn.py", line 116, in _main
    self = pickle.load(from_parent)
EOFError: Ran out of input

我已经查看了我认为可能对此负责的代码,但我不知道multiprocessing在这里是如何相关的,因为我已经抓住了EOFError,或者所以它在我看来。 (请注意,此异常不会导致我的脚本退出。)

我最大的问题是,没有关于Python认为问题发生在哪里的信息。它指的是File "<string>", line 1, in <module>,这是无益的。如何确定实际引发异常的位置?

以下是我认为必须负责的方法,因为它是我使用的唯一地方multiprocessing

# imported earlier:
import multiprocessing as mp

def _play(self, name):
    '''Plays the sound given by name'''
    if self.silent:
        return True
    def play_sound(q=None):  # Called in a separate process so playing the sound doesn't block anything else.
        '''q is a multiprocessing.Queue object for interprocess communication.'''
        try:
            snd = self.sounds[name]
            if self._use_subprocess:
                s = subprocess
                return s.call([self.player, snd], stdout=s.DEVNULL, stderr=s.DEVNULL, timeout=20)
            else:
                return self.player(snd, self._winsound_options)
        except (KeyboardInterrupt, EOFError):
            sys.exit(0)
        except subprocess.TimeoutExpired as e:
            #if q:
            #    q.put(e)
            sys.stderr.write('\nSOUND ERROR: Unable to play the sound "{}": Timeout expired.\n\n'.format(snd))
            sys.exit(1)
        except FileNotFoundError:
            sys.stderr.write('\nSOUND ERROR: Unable to locate the sound player "{}".\n\n'.format(self.player))
            sys.exit(2)
        except EOFError:
            pass
    #q = mp.Queue()
    proc_name = 'Play sound: {}; time: {}'.format(name, datetime.datetime.now().strftime('%I:%M:%S %p'))
    try:
        proc = mp.Process(target=play_sound, name=proc_name)#, args=(q,))
        proc.start()
    # On Windows, multiprocessing attempts to pickle this method, which fails
    # because it's called by an inner function defined in __getattr__. We'll
    # Skip using multiprocessing in this case.
    # References: https://github.com/ouspg/trytls/issues/196 and http://stackoverflow.com/a/36995008/713735
    except (AttributeError, EOFError):
        play_sound()

1 个答案:

答案 0 :(得分:0)

我仍然不理解我所获得的追溯,但我通过改变来解决这个问题:

proc = mp.Process(target=play_sound, name=proc_name)
proc.start()

为:

if os.name == 'nt':
    play_sound()
else:
    proc = mp.Process(target=play_sound, name=proc_name)
    proc.start()

是的,我以这种方式失去了功能,但由于缺少一个好的终端,脚本已经在Windows上瘫痪了。 (而且我对Windows并不十分了解。)