假设一个应用程序一次支持两个调用。第一个呼叫已连接,第二个呼叫正在进入。其中一个呼叫正在进行"结束呼叫&接听电话","拒绝","保持通话和接听电话"的按钮。
如果是"结束通话&接听电话",表示结束已连接的电话并接听新电话。 如果"拒绝",则意味着拒绝接听电话。
在两种情况下代表
- (void)provider:(CXProvider *)provider performEndCallAction:(CXEndCallAction *)action
被触发。现在,如何知道哪一个呼叫结束,来电或已经连接的呼叫? CXEndCallAction
并未说明"拒绝"也不是"已经结束的电话"
有没有人有解决方案?
答案 0 :(得分:2)
我发现有一个交易清单代表:
- (BOOL)provider:(CXProvider *)provider executeTransaction:(CXTransaction *)transaction
如果有一个事务会触发其他代表CXSetHeldCallAction
或CXEndCallAction
,那么实现此代理将提供足够的信息。所以现在我可以决定触发什么动作,并在必要时绕过其他代表。
这是我的代码,如果其他人正在努力:
- (BOOL)provider:(CXProvider *)provider executeTransaction:(CXTransaction *)transaction
{
NSLog(@"executeTransaction : %@", transaction.debugDescription);
BOOL callEnd = NO;
BOOL callHold= NO;
BOOL callAnswer = NO;
NSPredicate *filter = [NSPredicate predicateWithFormat:@"self isKindOfClass: %@", [CXEndCallAction class]];
NSArray *ends = [transaction.actions filteredArrayUsingPredicate:filter];
callEnd = [ends count] >= 1;
filter = [NSPredicate predicateWithFormat:@"self isKindOfClass: %@", [CXAnswerCallAction class]];
NSArray *answer = [transaction.actions filteredArrayUsingPredicate:filter];
callAnswer = [answer count] >= 1;
filter = [NSPredicate predicateWithFormat:@"self isKindOfClass: %@", [CXSetHeldCallAction class]];
NSArray *hold = [transaction.actions filteredArrayUsingPredicate:filter];
callHold = [hold count] >= 1;
if(callEnd && callAnswer)
{
actionType = kCallKitEndAndAnswer;
[[MyCallManager sharedManager] endPreviousCallAndAnswerNewCall:^(BOOL succeeded) {
NSLog(@"end answered call: %@", succeeded ? @"yes" : @"No");
CXEndCallAction *en = [ends firstObject];
succeeded ? [en fulfill] : [en fail];
CXAnswerCallAction *an= [answer firstObject];
succeeded ? [an fulfill] : [an fail];
}];
return YES;
}
else if(callHold && callAnswer)
{
actionType = kCallKitHoldAndAnswer;
[[MyCallManager sharedManager] answerCall:^(BOOL succeeded) {
NSLog(@"hold answered call: %@", succeeded ? @"yes" : @"No");
CXSetHeldCallAction *ho = [hold firstObject];
succeeded ? [ho fulfill] : [ho fail];
CXAnswerCallAction *an= [answer firstObject];
succeeded ? [an fulfill] : [an fail];
}];
return YES;
}
else if([hold count] == 2)
{
[[MyCallManager sharedManager] swapCalls];
usleep(25000);
CXSetHeldCallAction * fi = [hold firstObject];
CXSetHeldCallAction * la = [hold lastObject];
[fi fulfill];
[la fulfill];
return YES;
}
return NO;
}
答案 1 :(得分:1)
您需要访问CXEndCallAction的callUUID成员。
在正确的对象上调用事务,因此您只需终止与传输的UUID匹配的调用。这意味着您必须将UUID的支持添加到您自己的调用对象模型中。
答案 2 :(得分:0)
您可以使用enum和“isMemberOfClass”。
在providerDelegate.h
中 // Call Modes.
typedef NS_ENUM(NSUInteger, CallMode) {
kUnknownMode = 0,
kEndAndAnswerMode = 1,
kHoldAndAnswerMode = 2
};
在providerDelegate.m
中@property(nonatomic, assign) CallMode mode;
并添加以下代码以获取每笔交易。
- (BOOL)provider:(CXProvider *)provider executeTransaction:(CXTransaction *)transaction {
NSLog(@"Provider execute transaction");
BOOL callEnd = NO;
BOOL callHold= NO;
BOOL callAnswer = NO;
NSPredicate *filter = [NSPredicate predicateWithFormat:@"self isMemberOfClass: %@", [CXEndCallAction class]];
NSArray<CXEndCallAction *> *ends = [transaction.actions filteredArrayUsingPredicate:filter];
callEnd = [ends count] >= 1;
filter = [NSPredicate predicateWithFormat:@"self isMemberOfClass: %@", [CXAnswerCallAction class]];
NSArray<CXAnswerCallAction *> *answers = [transaction.actions filteredArrayUsingPredicate:filter];
callAnswer = [answers count] >= 1;
filter = [NSPredicate predicateWithFormat:@"self isMemberOfClass: %@", [CXSetHeldCallAction class]];
NSArray<CXSetHeldCallAction *> *holds = [transaction.actions filteredArrayUsingPredicate:filter];
callHold = [holds count] >= 1;
if(callEnd && callAnswer) {
_mode = kEndAndAnswerMode;
} else if(callHold && callAnswer) {
_mode = kHoldAndAnswerMode;
} else {
_mode = kUnknownMode;
}
return NO;
}