Question

我必须执行此查询

Agent.sources.Netcat.selector.type = replicating

我在yii2-

中写了这样的查询

select count(id) as numberofcompanies, sum(offered_value) as total_offered_value from campaign_comapany
       where ( campaign_id in (select id from campaing where user_id = current_user ) or campaing_company.sp_user_id = current_user)
             and campaign_company.status = '3'

但它给了我$query->select(['count(id) as numberofcompanies','sum(offered_value) as total_offered_value']) ->from('campaign_company') ->andFilterWhere(['or',['in','campaign_id',(new yii\db\Query())->select(['id'])->from('campaign')->where(['=','user_id',Yii::$app->user->id])],['=','campaign_company.sp_user_id',Yii::$app->user->id]]) ->andWhere(['=','status','3']) ->one();的错误但是如果我只是使用unknow column campaign_company.user_id就像下面那样工作 -

where

我应该怎么做才能得到sql查询的结果，我不想两次打到数据库服务器，提前谢谢

Answer 1

因为很难遵循你的逻辑。要简化代码和查询，请将第一个条件添加为普通sql。此外，由于需要第二个条件，您可以按如下方式交换位置：

$query
    ->select(['count(id) as numberofcompanies','sum(offered_value) as total_offered_value'])
    ->from('campaign_company')
    ->where(['status' => '3'])
    ->andWhere(['
        campaign_id in (select id from campaign where user_id = :current_user )
        or campaign_company.sp_user_id = :current_user1', 
        [':current_user' => Yii::$app->user->id, ':current_user1' => Yii::$app->user->id]])
    ->one();

Answer 2

使用join：

$query->select(['count(id) as numberofcompanies','sum(offered_value) as total_offered_value'])
       ->from('campaign_company')
       ->innerJoin('campaign','`campaign`.`id` = `campaign_company`.`campaign_id`') 
       ->where([
           ['=','campaign.user_id',Yii::$app->user->id])],
           ['=','campaign.campaign_company.sp_user_id',Yii::$app->user->id],
           ['=','campaign_company.status','3']
         ]
       ->one();

在yii2中的andFilterWhere中的子查询

2 个答案: