<span>
<img src="images/author2.jpg" width="50" /> //in Database i have profilepic/userimage.jpg and the image shown in above is a static image.
<input class="searchStudent" type="text" autocomplete="off">
</span>
我已输入字母“A”,响应将以数组形式出现。我想显示用户的照片和名称,我该怎么做...?
这是我从脚本中获取详细信息:
/*Search Student starts here*/
$(document).on("focus keyup", "input.searchStudent", function (event) {
$(this).autocomplete({
source: 'gdcontroller.php?action=search',
select: function (event, ui) {
event.preventDefault();
this.value = ui.item.label;
},
focus: function (event, ui) {
event.preventDefault();
this.value = ui.item.label;
}
});
});
/*Search Student ends here*/
这是我的控制器,我在这里搜索名为“A”的学生 并提取他们的详细信息:
if($_GET['action']=="search" && $_GET['term']!='')
{
$keysearch = $_GET['term'];
$studentValue = trim($_GET['studentname']);
$studentsQuery =$conn->query('select s.student_pid,i.email,s.student_email,s.student_fname,s.student_lname,s.profile_pic from r_job_invitations i
LEFT JOIN tbl_students s ON i.email = s.student_email where i.id_job =54 and accounttype = 1 and inv_res = 1 and student_fname LIKE "'.$keysearch.'%" OR student_lname LIKE "'.$keysearch.'%" ')or die(mysqli_error());
$studentData = array();
while($student = $studentsQuery->fetch_assoc()){
$studentData[]= $student;
}
echo json_encode($studentData);
exit;
}
答案 0 :(得分:0)
<div id="photoContainer"></div>
$(document).on("focus keyup", "input.searchStudent", function(event) {
$(this).autocomplete({
source: 'gdcontroller.php?action=search',
select: function (event, ui) {
event.preventDefault();
//I'm having trouble here; even name is not coming:
student.student_fname.value = ui.item.student.student_fname;
$("#photoContainer").append('<img src="' + ui.item.student.profile_pic + '">');
},
focus: function(event, ui) {
event.preventDefault();
this.value = ui.item.label;
}
});
});