Question

我试图从R中的句子中提取精确的短语。它还提取其部分匹配的句子。例如：

  phrase <- c("r is not working","roster is not working")
  sentence <- c("ABC is not working and roster is not working","CDE is working but printer is not working")

  extract <- sapply(phrase, grepl, x = sentence)
  extract

它将输出显示为：

              r is not working      roster is not working
  [1,]             TRUE                  TRUE
  [2,]             TRUE                 FALSE

我想要的输出是：

              r is not working      roster is not working
  [1,]               FALSE                  TRUE
  [2,]               FALSE                  FALSE

短语＆＃34; r不起作用＆＃34;不应该与两个句子匹配。有没有办法解决这个问题。有什么想法吗？谢谢！

Answer 1

grepl评估正则表达式。

如果你想坚持这些，锚定你的搜索模式到字符串的开头和结尾：

phrase <- c("^r is not working$", "^roster is not working$")

如果您想要检查完全匹配，只需使用

即可

extract <- sapply(sentence, `%in%`, phrase)

无法从R中的句子中提取精确的短语

1 个答案: