尝试将每个数字乘以数组位置,并且它出现错误:
def the_sum(number)
i = 0
number = 0
ans = 0
while i < 0
ans = string[idx] * string.index
i += idx
end
return ans
end
test =
the_sum([2, 3]) == 3 # (2*0) + (3*1)
the_sum([2, 3, 5]) == 13 # (2*0) + (3*1) + (5*2)
它出来了?
答案 0 :(得分:1)
这里有一些问题
def the_sum(number)
i = 0
number = 0 # You just cleared your input variable!
ans = 0
while i < 0 # You previously i = 0 so this will never be true
ans = string[idx] * string.index
i += idx
end
return ans # Ans is and was always 0
end
可以通过调用您传递的each_with_index
上的Array
来解决此问题。
def the_array_sum(array)
ans = 0
array.each_with_index do |val, index|
ans += val * index
end
return ans
end
the_array_sum([2, 3]) == 3
# => true
the_array_sum([2, 3, 5]) == 13
# => true