正如标题所说,我使用设计中的用户名和密码字段正确注册。但是,当我尝试登录时,显示'Invalid Email, Login or password'
。用户名存储在rails控制台上,但密码未加密或显示在此处:
=> #<ActiveRecord::Relation [#<User id: 9, email: "", created_at: "2016-12-01 16:32:20", updated_at: "2016-12-01 16:32:20", username: "benjamin">]>
应用程序控制器:
class ApplicationController < ActionController::Base
protect_from_forgery with: :exception
before_action :authenticate_user!
before_action :configure_permitted_parameters, if: :devise_controller?
protected
def configure_permitted_parameters
added_attrs = [:username, :email, :password, :password_confirmation, :remember_me]
devise_parameter_sanitizer.permit :sign_up, keys: [:username, :password]
devise_parameter_sanitizer.permit :account_update, keys: [:username, :password]
end
end
User.rb:
class User < ApplicationRecord
# Include default devise modules. Others available are:
# :confirmable, :lockable, :timeoutable and :omniauthable
has_many :stories
validates :username, :presence => true, :uniqueness => { :case_sensitive => false}
validates_format_of :username, with: /^[a-zA-Z0-9_\.]*$/, :multiline => true
attr_accessor :login
devise :database_authenticatable, :registerable,
:recoverable, :rememberable, :trackable, :validatable, :authentication_keys => {email: true, login: false}
def self.find_for_database_authentication(warden_conditions)
conditions = warden_conditions.dup
if login = conditions.delete(:login)
where(conditions.to_h).where(["lower(username) = :value OR lower(email) = :value", { :value => login.downcase }]).first
elsif conditions.has_key?(:username) || conditions.has_key?(:email)
where(conditions.to_h).first
end
end
def email_required?
false
end
def email_changed?
false
end
end
我的数据库文件相关:
class DeviseCreateUsers < ActiveRecord::Migration[5.0]
def change
create_table :users do |t|
## Database authenticatable
t.string :email, null: false, default: ""
t.string :encrypted_password, null: false, default: ""
## Recoverable
t.string :reset_password_token
t.datetime :reset_password_sent_at
## Rememberable
t.datetime :remember_created_at
## Trackable
t.integer :sign_in_count, default: 0, null: false
t.datetime :current_sign_in_at
t.datetime :last_sign_in_at
t.string :current_sign_in_ip
t.string :last_sign_in_ip
## Confirmable
# t.string :confirmation_token
# t.datetime :confirmed_at
# t.datetime :confirmation_sent_at
# t.string :unconfirmed_email # Only if using reconfirmable
## Lockable
# t.integer :failed_attempts, default: 0, null: false # Only if lock strategy is :failed_attempts
# t.string :unlock_token # Only if unlock strategy is :email or :both
# t.datetime :locked_at
t.timestamps null: false
end
add_index :users, :email, unique: true
add_index :users, :reset_password_token, unique: true
# add_index :users, :confirmation_token, unique: true
# add_index :users, :unlock_token, unique: true
end
end
/
class RemoveEmailUniquenessFromUser < ActiveRecord::Migration[5.0]
def change
change_column :users, :email, :string, unique: false
end
end
/
class RemoveIndexFromUsersEmail < ActiveRecord::Migration[5.0]
def change
remove_index :users, :email
end
end
编辑:
I have changed devise params to:
def configure_permitted_parameters
added_attrs = [:username, :email, :password, :password_confirmation, :remember_me]
devise_parameter_sanitizer.permit :sign_in, keys: [:username, :password]
devise_parameter_sanitizer.permit :sign_up, keys: [:username, :password, :password_confirmation]
devise_parameter_sanitizer.permit :account_update, keys: [:username, :password, :password_confirmation]
end
仍然是'无效,电子邮件,登录或密码'
答案 0 :(得分:0)
在这里:
def configure_permitted_parameters
added_attrs = [:username, :email, :password, :password_confirmation, :remember_me]
devise_parameter_sanitizer.permit :sign_up, keys: [:username, :password]
devise_parameter_sanitizer.permit :account_update, keys: [:username, :password]
end
您没有使用added_attrs
变量。我猜你还需要允许那些领域。