我正在阅读java实现中的队列。我找到了以下代码
public class QueueOfStrings {
private Node first = null; // least-recently added
private Node last = null; // most-recently added
private class Node {
private String item;
private Node next;
}
// is the queue empty?
public boolean isEmpty() {
return first == null;
}
public String dequeue() {
if (isEmpty()) {
throw new RuntimeException("Queue underflow");
}
String item = first.item;
first = first.next;
return item;
}
public void enqueue(String item) {
Node x = new Node();
x.item = item;
if (isEmpty()) {
first = x;
last = x;
} else {
last.next = x;
last = x;
}
}
我确实以这样的方式重写了它们:
public String dequeue() {
if (isEmpty()) {
throw new RuntimeException("Queue underflow");
} else if (first = last) {
String f = first.item;
first = null;
last = null;
return f;
}
String f = first.item;
first = first.next;
return f;
}
public void enqueue(String item) {
Node x = new Node(item);
if (first = last = null) {
first = last = x;
}
last.next = x;
last = x;
}
我在dequeue()和enqueue()方法中做得对吗?
在主要方法中我应该这样做:
public static void main(String[] args) {
QueueOfStrings q = new QueueOfStrings();
q.enqueue("roro");
q.enqueue("didi");
q.enqueue("lala");
System.out.println(q.dequeue());
}
由于
答案 0 :(得分:4)
public String dequeue() {
if (isEmpty()) {
throw new RuntimeException("Queue underflow");
} else if (first == last) {
String f = first.item;
first = null;
last = null;
return f;
}
String f = first.item;
first = first.next;
return f;
}
public void enqueue(String item) {
Node x = new Node(item);
if (first == null && last == null) {
first = x;
last = x;
return; // return back when first node is enqueued
}
last.next = x;
last = x;
}