Question

所以，我有一个数据库，我已经以多种方式导入Postgresql，直接使用命令行或pgadmin3，但所有尝试都给我同样的问题：使用简单脚本时我无法查询任何内容比如

class BaseClass(object):
    def __init__(self, base_arg, base_arg2=None, *args, **kwargs):
        print "\tBaseClass: {}, {}".format(base_arg, base_arg2)
        try:
            super(BaseClass, self).__init__(*args, base_arg=base_arg, base_arg2=base_arg2, **kwargs)
        except:
            super(BaseClass, self).__init__()

class MixinClass(object):
    def __init__(self, mixin_arg, *args, **kwargs):
        print "\tMixinClass: {}".format(mixin_arg)
        try:
            super(MixinClass, self).__init__(*args, mixin_arg=mixin_arg, **kwargs)
        except:
            super(MixinClass, self).__init__()

class MixinClassB(object):
    def __init__(self, mixin_arg, *args, **kwargs):
        print "\tMixinClassB: {}".format(mixin_arg)
        try:
            super(MixinClassB, self).__init__(*args, mixin_arg=mixin_arg, **kwargs)
        except:
            super(MixinClassB, self).__init__()

class ChildClassA(BaseClass, MixinClass):
    """
    Let's make it work for this case
    """
    def __init__(self, base_arg, mixin_arg, base_arg2=None):
        print "Initializing {}: base_arg: {} mixin_arg: {} base_arg2: {}".format(
            self.__class__.__name__, base_arg, mixin_arg, base_arg2)
        super(ChildClassA, self).__init__(base_arg=base_arg, mixin_arg=mixin_arg, base_arg2=base_arg2)        


class ChildClassC(BaseClass, MixinClassB, MixinClass):
    """
    Now let's simply add another mixin: before...
    """
    def __init__(self, base_arg, mixin_arg, base_arg2=None):
        print "Initializing {}: base_arg: {} mixin_arg: {} base_arg2: {}".format(
            self.__class__.__name__, base_arg, mixin_arg, base_arg2)
        super(ChildClassC, self).__init__(base_arg=base_arg, mixin_arg=mixin_arg, base_arg2=base_arg2)

class ChildClassD(BaseClass, MixinClass, MixinClassB):
    """
    Now let's simply add another mixin: ..and after
    """
    def __init__(self, base_arg, mixin_arg, base_arg2=None):
        print "Initializing {}: base_arg: {} mixin_arg: {} base_arg2: {}".format(
            self.__class__.__name__, base_arg, mixin_arg, base_arg2)
        super(ChildClassD, self).__init__(base_arg=base_arg, mixin_arg=mixin_arg, base_arg2=base_arg2)        

try:
    base = BaseClass(1, 2)
except Exception as e:
    print "Failed because object.__init__ does not expect any argument ({})".format(e)
childA = ChildClassA(1, 3, 2)  # note the order of the arguments - the mixin arg is interleaved
childC = ChildClassC(1, 3, 2)
childD = ChildClassD(1, 3, 2)

因为我遇到“关系不存在”。

我已经搜索过高低，我发现错误是由使用大写字母等的数据库名称冲突引起的，但你可以看到我不应该有这个问题，因为我没有使用过小写字母。

所以我完全迷失了该怎么做。是的，我真的还在学习postgresql中的绳索，所以如果它只是一个非常基本的东西，就像我错过了一个选项，请原谅我！这个image显示了我得到的错误以及您可能需要的更多信息。

我正在使用虚拟机


VMware Workstation

Ubuntu 15.04

Postgresql 9.4

pgAdmin3 v1.20

提前致谢！

使用pgadmin3无法在Postgresql 9.4中查询任何内容

0 个答案: