Question

我在SQL Server中有两个表，

Declare @Table1 Table ( TID1 INT, TP1 INT)

Declare @Table2 Table ( TID2 INT, TP2 INT)


INSERT INTO @Table1 (TID1,TP1) VALUES (100,1)
INSERT INTO @Table1 (TID1,TP1) VALUES (100,2)
INSERT INTO @Table1 (TID1,TP1) VALUES (100,3)

INSERT INTO @Table2 (TID2,TP2) VALUES (101,1)
INSERT INTO @Table2 (TID2,TP2) VALUES (101,2)
INSERT INTO @Table2 (TID2,TP2) VALUES (101,3)
INSERT INTO @Table2 (TID2,TP2) VALUES (102,1)
INSERT INTO @Table2 (TID2,TP2) VALUES (102,2)
INSERT INTO @Table2 (TID2,TP2) VALUES (103,1)
INSERT INTO @Table2 (TID2,TP2) VALUES (103,2)
INSERT INTO @Table2 (TID2,TP2) VALUES (103,3)
INSERT INTO @Table2 (TID2,TP2) VALUES (103,4)
INSERT INTO @Table2 (TID2,TP2) VALUES (104,2)
INSERT INTO @Table2 (TID2,TP2) VALUES (105,3)

将数据作为：

TID1        TP1
----------- -----------
100         1
100         2
100         3


TID2        TP2
----------- -----------
101         1
101         2
101         3
102         1
102         2
103         1
103         2
103         3
103         4
104         2
105         3

我想选择那些与Table2 TP2列中的TP1列完全匹配的记录。具有ID 101的EX TID2将仅在结果集

中

Answer 1

SELECT t2.TID2
FROM @Table2 t2
LEFT JOIN @Table1 t1
    ON t2.TP2 = t1.TP1
GROUP BY t2.TID2
HAVING SUM(CASE WHEN t1.TP1 IS NULL THEN 1 ELSE 0 END) = 0 AND
       COUNT(*) = (SELECT COUNT(*) FROM @Table1)

Answer 2

尝试如下。

SELECT TID2
FROM   @TABLE1 T
       RIGHT JOIN  @TABLE2 T2
         ON T.TP1 = T2.TP2
GROUP  BY TID2
HAVING COUNT(T2.TP2) = (SELECT COUNT(*) FROM @TABLE1)

Answer 3

-- you can calculated this in CTEW or sub-query if you do not like to be in variable
DECLARE @MaxRowsCount INT = (SELECT COUNT(*) FROM @Table1);

SELECT T2.[TID2]
FROM @Table2 T2
LEFT JOIN @Table1 T1
    ON T2.[TP2] = T1.[TP1]
GROUP BY T2.[TID2]
HAVING
(
    -- current count of rows should be the same as the row count from the first table
    COUNT(T2.[TP2]) = @MaxRowsCount
)

如何在SQL中查找与另一个表匹配的表的行组？

3 个答案: