Question

以下是Oracle 10g中出勤率表中 Record_Date （日期）列中的可用日期。您可以找到日期04/06/2016 08/06 / 2016年16/06/2016 23/06/2016 29/06/2016序列中缺失。

   **Record_Date**  

    01/06/2016
    02/06/2016
    03/06/2016
    05/06/2016
    06/06/2016
    07/06/2016
    09/06/2016
    10/06/2016
    12/06/2016
    13/06/2016
    14/06/2016
    15/06/2016
    17/06/2016
    18/06/2016
    19/06/2016
    20/06/2016
    21/06/2016
    22/06/2016
    24/06/2016
    25/06/2016
    26/06/2016
    27/06/2016
    28/06/2016
    30/06/2016
    01/07/2016

我只需要一个查询来查找特定月份（以及之后的年份）中的缺失日期。

请告诉我一个方法

Answer 1

with 
nums(num )
as
(select 0 from dual
union all
select num + 1 from nums
  where num < (select max(col) from qtable)- (select min(col) from qtable)
),

date_btwn(dat) 
as(select num + (select min(col) from qtable) from nums)

select  dat from date_btwn
minus
select col from qtable;

内联观看次数 nums将生成要从开始日期添加的所有数字。 date_btwn 包含表格中开始日期和结束日期之间的所有日期。我们使用减号来排除表格中的日期。

Answer 2

你可以使用这个：

WITH all_days AS 
    (SELECT DATE '2016-06-01' + LEVEL-1 AS the_day
    FROM dual
    CONNECT BY DATE '2016-06-01' + LEVEL-1 <= DATE '2016-06-30')
SELECT the_day
FROM all_days
WHERE the_day <>ALL (SELECT Record_Date FROM Attendance);

或者，如果您想更动态地使用它：

WITH all_days AS 
    (SELECT START_DATE + LEVEL AS the_day
    FROM dual
        CROSS JOIN 
            (SELECT 
                TRUNC(MIN(Record_Date), 'MM') -1 AS START_DATE, 
                TRUNC(LAST_DAY(MAX(Record_Date))) AS END_DATE 
            FROM Attendance)
    CONNECT BY START_DATE + LEVEL <= END_DATE)
SELECT the_day
FROM all_days
WHERE the_day <>ALL (SELECT Record_Date FROM Attendance);

注意，<>ALL与NOT IN相同 - 这只是我个人的偏好。

Answer 3

您需要生成所有日期，并且您必须找到遗失的日期。下面用cte我已经完成了

使用CTE和not in查询：

            with calendar as (
                    select rownum - 1 as daynum,
                    to_date('1-jun-2016') + (rownum - 1) as monthdate
                    from dual )
            select monthdate  as monthdate
            from calendar              
            where monthdate  not in (
            SELECT 
            Record_Date
            FROM Attendance      )  
             and monthdate   >=  to_date('1-jun-2016')  /* CHANGE as per need */
             and monthdate   <  to_date('1-jul-2016')  /* CHANGE as per need */

或使用CTE和left join查询：

            with calendar as (
                    select rownum - 1 as daynum,
                    to_date('1-jun-2016') + (rownum - 1) as monthdate
                    from dual )
            select monthdate  as monthdate
            from calendar C left join Attendance A on A.Record_Date=c.monthdate
            where A.Record_Date is  null
             and monthdate   >=  to_date('1-jun-2016')  /* CHANGE as per need */
             and monthdate   <  to_date('1-jul-2016')  /* CHANGE as per need */

根据datecolumn格式，首先将其更改为validformat到选择查询，然后使用此查询。

查询以查找Oracle中缺少的一个月的日期

3 个答案: