Question

我有下一个sql查询：

SELECT 
    @row_number:=@row_number+1 AS ID, IGN_DATES.PLACA, IGN_DATES.FECHA, OFF_DATES.FECHA
FROM
    (SELECT 
        a.PLACA AS PLACA, MIN(p.FECHA_GPS) AS FECHA
    FROM
        POSICIONHISTORIAL p
    JOIN AUTOMOVIL a ON p.SECAUTOMOVIL = a.SECAUTOMOVIL
    JOIN EVENTO e ON p.EVENTO_SECEVENTO = e.SECEVENTO
    WHERE
        p.FECHA_GPS BETWEEN '2016-09-01' AND '2016-10-01'
            AND e.CODIGO = 'ENC'
            AND a.PLACA IN ('SHS946', 'SHT011')
    GROUP BY a.PLACA , DAY(p.FECHA_GPS)) AS IGN_DATES
        JOIN
    (SELECT 
        a.PLACA AS PLACA,
            SUBSTRING_INDEX(GROUP_CONCAT(p.FECHA_GPS
                ORDER BY p.FECHA_GPS DESC
                SEPARATOR ' , '), ',', 2) AS FECHA
    FROM
        POSICIONHISTORIAL p
    JOIN AUTOMOVIL a ON p.SECAUTOMOVIL = a.SECAUTOMOVIL
    JOIN EVENTO e ON p.EVENTO_SECEVENTO = e.SECEVENTO
    WHERE
        p.FECHA_GPS BETWEEN '2016-09-01' AND '2016-10-01'
            AND e.CODIGO = 'APA'
            AND a.PLACA IN ('SHS946', 'SHT011')
    GROUP BY a.PLACA , DAY(p.FECHA_GPS)) 
AS OFF_DATES ON DATE(IGN_DATES.FECHA) = DATE(OFF_DATES.FECHA),
(SELECT @row_number:=0) AS t;

我使用mysql 5.7，这个查询的结果是：

Result Set in Mysql

但是从JPA 2.1（Hibernate）调用的本机查询返回OFF_DATES.FECHA的重复值，这是来自eclipse调试的值。

Result set in JPA

声明中的rowid是意图解决问题的聚合，但这是不成功的

感谢您的帮助。

Answer 1

我解决了这个问题，问题不在于One-To-Many relationship gets duplicate objects whithout using "distinct".Why?。

问题是用于连接的列，我添加了一列：

SELECT 
    @row_number:=@row_number+1 AS ID, IGN_DATES.PLACA, IGN_DATES.FECHA, OFF_DATES.FECHA
FROM
    (SELECT 
        a.PLACA AS PLACA, MIN(p.FECHA_GPS) AS FECHA
    FROM
        POSICIONHISTORIAL p
    JOIN AUTOMOVIL a ON p.SECAUTOMOVIL = a.SECAUTOMOVIL
    JOIN EVENTO e ON p.EVENTO_SECEVENTO = e.SECEVENTO
    WHERE
        p.FECHA_GPS BETWEEN '2016-09-01' AND '2016-10-01'
            AND e.CODIGO = 'ENC'
            AND a.PLACA IN ('SHS946', 'SHT011')
    GROUP BY a.PLACA , DAY(p.FECHA_GPS)) AS IGN_DATES
        JOIN
    (SELECT 
        a.PLACA AS PLACA,
            SUBSTRING_INDEX(GROUP_CONCAT(p.FECHA_GPS
                ORDER BY p.FECHA_GPS DESC
                SEPARATOR ' , '), ',', 2) AS FECHA
    FROM
        POSICIONHISTORIAL p
    JOIN AUTOMOVIL a ON p.SECAUTOMOVIL = a.SECAUTOMOVIL
    JOIN EVENTO e ON p.EVENTO_SECEVENTO = e.SECEVENTO
    WHERE
        p.FECHA_GPS BETWEEN '2016-09-01' AND '2016-10-01'
            AND e.CODIGO = 'APA'
            AND a.PLACA IN ('SHS946', 'SHT011')
    GROUP BY a.PLACA , DAY(p.FECHA_GPS)) 
AS OFF_DATES ON DATE(IGN_DATES.FECHA) = DATE(OFF_DATES.FECHA)
AND IGN_DATES.PLACA = OFF_DATES.PLACA,
(SELECT @row_number:=0) AS t;

jpa中的结果集whit whit重复行（Hibernate）

1 个答案: