烧瓶TypeError:' ImmutableMultiDict'对象不可调用

时间:2016-12-01 02:13:37

标签: python html forms login flask

大家好,有人可以说这段代码有什么问题吗?我得到的错误:  TypeError:' ImmutableMultiDict'对象不可调用

def login():
error = None
form = LoginForm(request.form)

if request.method == 'POST':
    viewer = User.query.filter_by(Group='viewer').first()
    admin = User.query.filter_by(Group='admin').first()
    staff = User.query.filter_by(Group='staff').first()
    user = User.query.filter_by(Email=request.form(['email'])).first()
    password = User.query.filter_by(Password=request.form(['password'])).first()
    if (user or password) is None:
        session['logged_in'] = False
        flash('Please write your username password')
    else:

                session['logged_in'] = True
                flash('You were logged in')
                if viewer:
                    return redirect(url_for('viewer'))
                elif admin :
                    return redirect(url_for('admin'))
                elif staff:
                    return redirect(url_for('employee'))

return render_template('login.html', form=form)

这是一个HTML部分:

<form class="sa-innate-form" method="post">
                            {{ form.csrf_token }}
                            <label>Email Address</label>
                            <input type="text" name="email" value="{{ request.form.email }}">
                            <label>Password</label>
                            <input type="password" name="password" value="{{ request.form.password }}">
                            <button type="submit" value="submit">Sign In</button>
                            <a href="">Forgot Password?</a>
                        </form>

1 个答案:

答案 0 :(得分:4)

这里有语法错误:

user = User.query.filter_by(Email=request.form(['email'])).first()

相反它应该是:

user = User.query.filter_by(Email=request.form['email']).first()

还有其他几个例子,所以一定要抓住所有这些。这是一个错误的原因是您尝试使用字符串列表request.form调用['email']而不是索引到表单中。

if (user or password) is None:也有错误。如果其中任何一个不是None,则不会触发该块。但是,我认为理想的行为是要求两者兼顾。你可以试试这个:

if user is None or password is None:

或:

if None in [user, password]: