Question

我在表'配置'中有一列名为' message_notification '的列。我想在此列中将保存结果作为JSON对象生成：

border-color:transparent

表格，我用

message_notification: [
  {
    "alert" : "how are you doing today?"
  },
  {
    "alert" : "where have you been today?"
  }
]

如何实现这一目标？

[增订]

上面的代码将解析为ruby哈希（而不是JSON）

我的控制器

<%= simple_form_for(@configuration) do |f| %>
  Alert 1: <%= check_box_tag "configuration[message_notification][][alert]", 'how are you doing today?' %><label>Alert 1</label><br/>
  Alert 2: <%= check_box_tag "configuration[message_notification][][alert]", 'where have you been today?' %><label>Alert 2</label><br/>
  <%= f.submit %>
<% end %>

结果：

@configuration.message_notification = {
  alert: params[:message][:alert]
}.to_json

[更新2]

在控制台中：

message_notification: [
  {
    "alert" => "how are you doing today?"
  },
  {
    "alert" => "where have you been today?"
  }
]

Answer 1

您可以使用 to_json 将 ruby hash 转换为 JSON object

仅require 'json'中的controller。

params = {"utf8"=>"✓", "_method"=>"new", "authenticity_token"=>"txroAHF2+YZOrm48DtBZdVqKzxLYyHFq4+GWQFnM6kNldXgRZJMPv0yfj‌0/tfZVpuVvh39UVX4Fb66FNkkCZqA==", "message"=>{"name"=>"Dan Murphy Roundabout Test", "company"=>"transtech", "location_id"=>"", "message_notification"=>[{"alert"=>"alert1"}, {"alert"=>"alert2"}], "commit"=>"save", "controller"=>"message", "action"=>"create", "id"=>"1717"}}

由于您params object以上，根据您的要求，您可以使用，

<强> params['message']['message_notification'] = (params['message']['message_notification'].to_json)

这会将参数中的message_notification转换为json object，并存储在数据库中。

Answer 2

这就是我所做的。

  def resource_params
    params.require(:appointment_modules_dataset_intake).permit(
      :appointment_id,
      :main_issue,
      :cvf
    ).tap do |p|
      p[:cvf] = JSON.parse(p[:cvf]) # This is the significant line
    end
  end

Rails 4：在PostgreSQL中将值保存为JSON字符串对象/数组

2 个答案: