Question

在文本文件中，我有“abbcccdddd”。我想将“abcd”存储在一个数组中。

之前：tx [0] = a，tx [1] = b，tx [3] = c，tx [6] = d

之后：tx [0] = a，tx [1] = b，tx [2] = c，tx [3] = d

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

void main() 
{
    FILE *fp = fopen("D:\\C#\\Zip\\Text001.txt", "r");
    char x;
    int size;
    int j, k;
    int i = 0;

    fseek(fp, 0, SEEK_END);
    size = ftell(fp);
    fseek(fp, 0, SEEK_SET);
    char tx[size];
    x = fgetc(fp);

    while (x != EOF)
    {
        tx[i] = x;
        printf("%c", tx[i]);
        x = fgetc(fp);
        i++;
    }
}

Answer 1

remove_repeatation（）将执行此操作。

void remove_repeatation(char *str)
{
    char flag[256] = {0}; //Assuming sizeof char is 8. So max 256 different characters.
    int  i            = 0;
    int  j            = 0;

    for(i=0; str[i] != '\0';)
    {
        if(0 == flag[str[i]]) //Check if character is already found.
        {
            flag[str[i]] = 1; //If a character is found for the first time, enable corresponding flag.
            i++; //Go to next byte in the array.
        }
        else
        {
            for(j=i; str[j] != '\0'; j++)
                str[j] = str[j+1]; //If repeated character, shift the array entries to 1 byte left.
        }
    }
}

Answer 2

通过MayurK编辑上面的代码：

char* remove_repeatation(char *str)
{
    char flag[256] = {0}; //Assuming sizeof char is 8. So max 256 different characters.
    int  i            = 0;
    int  j            = 0;

    for(i=0; str[i] != '\0'; i++)
    {
        if(0 == flag[str[i]]) //Check if character is already found.
        {
            flag[str[i]] = 1; //If a character is found for the first time, enable corresponding flag.
            str[j] = str[i];
            j++;
        }
    }
    str[j] = '\0';
    return *str;
}

C删除char数组中的重复字符

2 个答案: