Question

class hive:
   def abc(str):
      name = str
      return name + ' welcome'

def main():
  obj = hive()
  print('enter name')
  string = input()
  print(obj.abc(string))

if __name__ == "__main__": main()

我想打印带有连接的欢迎字符串的名称，但我无法这样做，我收到以下错误：

C:\Users\SHUBHAM TANDAN\Desktop\python>class.py 
enter name
shubham
Traceback (most recent call last):
File "C:\Users\SHUBHAM TANDAN\Desktop\python\class.py", line 12, in <module>
if __name__ == "__main__": main()
File "C:\Users\SHUBHAM TANDAN\Desktop\python\class.py", line 10, in main
print(obj.abc(string))
TypeError: abc() takes 1 positional argument but 2 were given

有人可以帮我找到上面代码中的错误吗？

Answer 1

在python中创建类时，所有嵌套函数都必须具有＆＃39; self＆＃39;参数。

class hive:
   def abc(self, str):
      name = str
      return name + ' welcome'

在python中使用对象打印输出

1 个答案: