Question

我正在处理某个项目，但它有一个错误。该剧再次适合'不'。但每次输入“是”时它都会显示：

TIME TO PLAY HANGMAN
Do you want to play again (yes or no)?

这是我的整个代码

import random

def Hangman():
 print ('TIME TO PLAY HANGMAN')

wordlist =['apples', 'oranges', 'grapes', 'pizza', 'cheese', 'burger']
secret = random.choice(wordlist)
guesses = 'aeiou'
turns = 5

while turns > 0:
     missed = 0
     for letter in secret:
         if letter in guesses:
             print (letter,end=' ')
         else:
           print ('_',end=' ')
           missed= missed + 1

     print

     if missed == 0:
         print ('\nYou win!')
         break

     guess = input('\nguess a letter: ')
     guesses += guess

     if guess not in secret:
         turns = turns -1
         print ('\nNope.')
         print ('\n',turns, 'more turns')
         if turns < 5: print ('\n  |  ')
         if turns < 4: print ('  O  ')
         if turns < 3: print (' /|\ ')
         if turns < 2: print ('  |  ')
         if turns < 1: print (' / \ ')
         if turns == 0:
             print ('\n\nThe answer is', secret)

playagain = 'yes'
while playagain == 'yes': 
    Hangman()
    print('Do you want to play again? (yes or no)')
    playagain = input()

Answer 1

如果代码看起来像在编辑器中那样，那么问题是你没有在print('TIME TO PLAY HANGMAN')之后缩进所有代码，因此python认为它位于外部作用域并且只执行一次。它需要看起来像：

def Hangman():
    print ('TIME TO PLAY HANGMAN')
    wordlist =['apples', 'oranges', 'grapes', 'pizza', 'cheese', 'burger']
    # etc.

playagain = 'yes'
while playagain == 'yes':
    # etc.

Answer 2

你Hangman函数唯一能做的就是打印“玩游戏的时间”。其他一切都在功能之外。修复你的缩进，将游戏玩法循环放在函数中，它应该可以工作。

Answer 3

你陷入了while循环：

playagain = 'yes'
while playagain == 'yes': 
    Hangman()
    print('Do you want to play again? (yes or no)')
    playagain = input()

你的循环一直在寻找是否playagain == 'yes'。由于输入yes，因此运行while循环的条件仍然为真，这就是它再次运行并打印语句的原因。

我没有运行您的代码或检查其余部分，但根据您提供的问题，这应该是您的修复。

Python中的刽子手游戏

3 个答案: