我想使用Python包“Beautiful Soup”，但是来自Julia。当我尝试使用Julia包PyCall到达那里时，我得到一个错误。
https://github.com/JuliaPy/PyCall.jl/上的示例对我有用（plt.plot除外）
我执行以下操作：
ENV["PYTHON"]="C:\\Users\\AName\\Anaconda2\\python.exe"
Pkg.build("PyCall")
using PyCall
@pyimport bs4 #need BeautifulSoup
markup=open("c:\\work\\theImData.xml","r")
soup = bs4.BeautifulSoup(PyTextIO(markup),"lxml")
并收到以下回复：
julia> soup = bs4.BeautifulSoup(PyTextIO(markup),"lxml")
ERROR: PyError (:PyObject_Call) <type 'exceptions.MemoryError'>
MemoryError('Julia exception: OutOfMemoryError()',)
File "C:\Users\AName\Anaconda2\lib\site-packages\bs4\__init__.py", line 191, in __init__
markup = markup.read()
File "PyCall.jl", line 1, in <lambda>
in pyerr_check at C:\Users\AName\.julia\v0.5\PyCall\src\exception.jl:56 [inlined]
in pyerr_check at C:\Users\AName\.julia\v0.5\PyCall\src\exception.jl:61 [inlined]
in macro expansion at C:\Users\AName\.julia\v0.5\PyCall\src\exception.jl:81 [inlined]
in #_pycall#62(::Array{Any,1}, ::Function, ::PyCall.PyObject, ::PyCall.PyObject, ::Vararg{Any,N}) at C:\Users\AName\.julia\v0
.5\PyCall\src\PyCall.jl:546
in _pycall(::PyCall.PyObject, ::PyCall.PyObject, ::Vararg{Any,N}) at C:\Users\AName\.julia\v0.5\PyCall\src\PyCall.jl:534
in #pycall#66(::Array{Any,1}, ::Function, ::PyCall.PyObject, ::Type{PyCall.PyAny}, ::PyCall.PyObject, ::Vararg{Any,N}) at C:\Users\B
jornPersson\.julia\v0.5\PyCall\src\PyCall.jl:568
in pycall(::PyCall.PyObject, ::Type{PyCall.PyAny}, ::PyCall.PyObject, ::Vararg{Any,N}) at C:\Users\AName\.julia\v0.5\PyCall\s
rc\PyCall.jl:568
in #call#67(::Array{Any,1}, ::PyCall.PyObject, ::PyCall.PyObject, ::Vararg{Any,N}) at C:\Users\AName\.julia\v0.5\PyCall\src\P
yCall.jl:571
in (::PyCall.PyObject)(::PyCall.PyObject, ::Vararg{Any,N}) at C:\Users\AName\.julia\v0.5\PyCall\src\PyCall.jl:571
为了确保.xml很小，我使用仅包含以下内容的.xml进行测试：
<?xml version="1.0"?>
<FacitData>
<DirectoryData directory="0028">
<Image fileName="image_0000911.png" />
</DirectoryData>
</FacitData>
我是否正确地调用了PyCall？