Question

我在SQLite中有一些奇怪的警告。这是什么意思？

11-30 13：05：23.653 9964-9964 / com.hikari.dev.servermonitor D / SQLiteDatabase：打开数据库 java.lang.Throwable：stacktrace 在android.database.sqlite.SQLiteDatabase.open（SQLiteDatabase.java:815）在android.database.sqlite.SQLiteDatabase.openDatabase（SQLiteDatabase.java:714）在android.app.ContextImpl.openOrCreateDatabase（ContextImpl.java:578）在android.content.ContextWrapper.openOrCreateDatabase（ContextWrapper.java:269）在android.database.sqlite.SQLiteOpenHelper.getDatabaseLocked（SQLiteOpenHelper.java:223）在android.database.sqlite.SQLiteOpenHelper.getReadableDatabase（SQLiteOpenHelper.java:187） - ＆GT;在com.hikari.dev.servermonitor.main.onClick（main.java:40）在android.view.View.performClick（View.java:5269）在android.view.View $ PerformClick.run（View.java:21556）在android.os.Handler.handleCallback（Handler.java:815）在android.os.Handler.dispatchMessage（Handler.java:104）在android.os.Looper.loop（Looper.java:207）在android.app.ActivityThread.main（ActivityThread.java:5769） at java.lang.reflect.Method.invoke（Native Method）在com.android.internal.os.ZygoteInit $ MethodAndArgsCaller.run（ZygoteInit.java:789）在com.android.internal.os.ZygoteInit.main（ZygoteInit.java:679）

database_helper.java（singleton）

package com.hikari.dev.servermonitor;

import android.content.Context;
import android.database.sqlite.SQLiteDatabase;
import android.database.sqlite.SQLiteOpenHelper;

public class database_helper extends SQLiteOpenHelper
{
    // Database
    public static final int DATABASE_VERSION = 1;
    public static final String DATABASE_NAME = "ServerMonitorDatabase";
    public static final String TABLE_SERVERS = "servers";

//Servers
public static final String SERVER_ID = "_id";
public static final String SERVER_NAME = "name";
public static final String SERVER_MONITORING_STATUS = "monitoring_status";
public static final String SERVER_IP = "ip";
public static final String SERVER_PORT = "port";

//Singleton
private static database_helper instance;

public static database_helper getInstance(Context context)
{
    if(instance == null)
        instance = new database_helper(context.getApplicationContext());
    return instance;
}

@Override
public void onCreate(SQLiteDatabase sqLiteDatabase)
{
    sqLiteDatabase.execSQL("create table " + TABLE_SERVERS + "(" + SERVER_ID
            + " integer primary key," + SERVER_NAME  + " text," + SERVER_MONITORING_STATUS
            + " integer," + SERVER_IP + " text," + SERVER_PORT + " integer)");
}

@Override
public void onUpgrade(SQLiteDatabase sqLiteDatabase, int i, int i1)
{
    sqLiteDatabase.execSQL("drop table if exists" + TABLE_SERVERS);

    onCreate(sqLiteDatabase);
}

private database_helper(Context context)
{
    super(context, DATABASE_NAME, null, DATABASE_VERSION);
}


}

main.java

(40)    SQLiteDatabase database = database_helper.getInstance(this).getReadableDatabase();

Answer 1

这里我在特定位置创建DATABASE：

MessageLocalDB msgDB;



String LocalDBMesage ="_chatdb.db";
        String FinalLocalDBName = Environment.getExternalStorageDirectory().getAbsolutePath() + "/Android/data/" + LocalDBMesage;
        msgDB= MessageLocalDB.getInstance(MainActivity.this,FinalLocalDBName);

在活动中：

msgDB.insertMSG(strSr,strenquiryID,"2323","DIvyesh",currentMSG,fdfg,msgStatus);

将数据写入数据库，如：

Cursor count=msgDB.fetchMSG(Integer.parseInt(strenquiryID));

读取数据：

{{1}}

Android SQLite警告

1 个答案: