Question

我正在尝试编写一个shell脚本来收集用户输入，以便稍后将其附加到文本文件中。以下是我正在使用的内容：

 note_file=~/project_2/file
 loop_test=y
 while test "$loop_test" = "y"
 do
  clear
  tput cup 1 4; echo "     Note Sheet Addition     "
  tput cup 2 4; echo "============================="
  tput cup 4 4; echo "Note: "
  tput cup 5 4; echo "Add Another? (Y)es or (Q)uit: "
  tput cup 4 10; read note
if test $note = "q"
then
 clear; exit
fi
 if test "$note" != ""
 then
  echo "$note:" >> $note_file
 fi
  tput cup 5 33; read hoop_test
 if [ "$hoop_test" = "q" ]
 then
  clear; exit
 fi
done

现在我的问题是我想在note变量中存储整个句子，而不仅仅是一个争论。即note =＆＃34;这是一个注释或其他一般文本内容＆＃34;

Answer 1

除了显而易见的hoop loop拼写问题，以及:附加到每个note（可能是故意的，dunno）之外，您的整个问题都会导致输入多个单词时出现的错误是您在使用test时未能引用您的变量，例如

    if test "${note,,}" = "q"   ## always quote variables in test

注意"..."（没有引号，它是test some words = "q"，它会提示错误：test: too many arguments - 听起来很熟悉吗？）正确引用它是test "some words" = "q"这很好。

（,,的参数展开只是将note的内容转换为小写以处理Q或q以便退出）

除了这些问题（并且需要在最后明确地将loop_test重置为y），您的脚本运行良好：

#!/bin/bash

note_file=~/project_2/file
note=""
loop_test=y

while test "$loop_test" = "y"
do
    clear
    tput cup 1 4; echo "     Note Sheet Addition     "
    tput cup 2 4; echo "============================="
    tput cup 4 4; echo "Note: "
    tput cup 5 4; echo "Add Another? (Y)es or (Q)uit: "
    tput cup 4 10; read note

    if test "${note,,}" = "q"   ## always quote variables in test
    then
        clear; exit
    fi

    if test "$note" != ""
    then
        echo "$note" >> "$note_file"
    fi

    tput cup 5 34; read loop_test

    if [ "${loop_test,,}" = "q" ]
    then
        clear; exit
    else
        loop_test=y
    fi
done

将用户输入集合到要附加到文件的变量中

1 个答案: