Question

我不认为我的return语句会传递所有测试用例（带有空字符串的测试用例）。 @FLOTUS没有提及，因为提及应该以空格进行，或者更确切地说是推文的开头。所以它应该作为一个空字符串传递。任何帮助将不胜感激如何解决这个问题！

def extract_mentions(tweet):
    ''' (str) -> list of str

Return a list containing all of the mentions in the tweet, in the order, they appear in the tweet.
Note: This definition of a mention doesn't allow for mentions embedded in other symbols.

Note: This definition of a mention doesn't allow for mentions embedded in other symbols.

>>> extract_mentions('@AndreaTantaros - You are a true journalistic professional. I so agree with what you say. Keep up the great work! #MakeAmericaGreatAgain')
['AndreaTantaros']
>>> extract_mentions('I'm joining @PhillyD tonight at 7:30 pm PDT / 10:30 pm EDT to provide commentary on tonight's #debate. Watch it here.')
['PhillyD']
>>> extract_mentions('Join me live in @Springfield, @ohio!')
['Springfield, ohio']
>>> extract_mentions('They endured beatings and jail time. They sacrificed their lives for this right@FLOTUS')
[''] '''

return [tag.strip('@') for tag in tweet.split() if tag.startswith('@')]

Answer 1

就个人而言，我会按照Wiktor评论中提出的一个很好的正则表达方式，但如果你想避免它，请尝试[tag[tag.index('@')+1:] for tag in tweet.split() if '@' in tag]

这样做，如果它在分割的标记中找到一个'@'字符，它将从@及其后的下一个字母返回该标记。例如，如果tag='b@a123，它将返回tag[2:]，即a123。

从列表中提取元素？

1 个答案: