Question

发送和获取文件并将其保存到文件夹的正确方法是什么？

我发邮件来自邮递员的身体形式数据：2个键＆＃39; uploadfile＆＃39;每个都有一个拉链。

此代码只有一个zip并保存，忽略第二个zip。

如何实现它来保存这两个文件？也。我应该在一个密钥中发送2个文件吗？或每个文件分开的键？

@RequestMapping(value = "/api/uploadFile", method = RequestMethod.POST)
@ResponseBody
public ResponseEntity<?> uploadFile(
        @RequestParam("uploadfile") MultipartFile uploadfile) {

    try {


            // Get the filename and build the local file path (be sure that the
            // application have write permissions on such directory)

            String filename = uploadfile.getOriginalFilename();
            String directory = "C://Develop//files";
            String filepath = Paths.get(directory, filename).toString();

            filenameZip = "c:/Develop/files/"+filename;
            directoryZip = "c:/Develop/files";

            // Save the file locally
            BufferedOutputStream stream =
                    new BufferedOutputStream(new FileOutputStream(new File(filepath)));
            stream.write(uploadfile.getBytes());
            stream.close();



    } catch (Exception e) {
        System.out.println(e.getMessage());
        return new ResponseEntity<>(HttpStatus.BAD_REQUEST);
    }
       // unzip(filenameZip, directoryZip);
        return new ResponseEntity<>(HttpStatus.OK);
} // method uploadFile

邮差记录：

var data = new FormData();
data.append("uploadfile", "pasta1.zip");
data.append("uploadfile", "pasta2.zip");

var xhr = new XMLHttpRequest();
xhr.withCredentials = true;

xhr.addEventListener("readystatechange", function () {
  if (this.readyState === 4) {
console.log(this.responseText);
  }
});

xhr.open("POST", "http://localhost:8080/api/uploadFile");
xhr.setRequestHeader("authorization", "Basic b3BlcmF0aW9uczpvcGVyYXRpb25z");
xhr.setRequestHeader("cache-control", "no-cache");
xhr.setRequestHeader("postman-token", "e7b6fcae-4a49-de34-ba7c-efd412fb244a");

xhr.send(data);

Answer 1

你可以让你的服务接受多部分文件的数组，然后你可以发送到你想要的文件上传它，这是一个例子

@RequestMapping(value="/multipleSave", method=RequestMethod.POST )
    public @ResponseBody String multipleSave(@RequestParam("file") MultipartFile[] files){
        String fileName = null;
        String msg = "";
        if (files != null && files.length >0) {
            for(int i =0 ;i< files.length; i++){
                try {
                    fileName = files[i].getOriginalFilename();
                    byte[] bytes = files[i].getBytes();
                    BufferedOutputStream buffStream = 
                            new BufferedOutputStream(new FileOutputStream(new File("F:/cp/" + fileName)));
                    buffStream.write(bytes);
                    buffStream.close();
                    msg += "You have successfully uploaded " + fileName +"<br/>";
                } catch (Exception e) {
                    return "You failed to upload " + fileName + ": " + e.getMessage() +"<br/>";
                }
            }
            return msg;
        } else {
            return "Unable to upload. File is empty.";
        }
    }
}

对于关键部分，您可以使用相同的密钥发送所有文件

正确的发送和获取文件的方式Spring

1 个答案: