Question

我想生成目标文本框值取决于具有以下条件的另一个文本框值 -

假设第一个 TextBox 值 - “ myfile名称”

如果第一个文本框值不以“副本”开头，则目标值将为“Copy of [1] myfile name”。
如果第一个文本框值“Copy of [1] myfile name”，则目标值将为“Copy of [2] myfile name”。
如果第一个文本框值“Copy of [2] myfile name”，则目标值将为“Copy of [3] myfile name”。

，即增加

如何使用jquery执行此操作？

HTML：

<div class="panel">
  <input type="text" id="filename" value="filename">
</div>
<div class="panel">
  <input type="text" id="newfilename" value="">
</div>
<div class="panel">
  <button type="button" id="btnGenerate">
    Get File Name
  </button>
</div>

JS：

$('#btnGenerate').click(function(){
  var newname;
    var oldname = $('#filename').val();
  if(typeof oldname !== undefined || oldname != ''){
    if(oldname.indexOf('Copy of')){
            var nCount = parseInt(oldname.match(/\([.*]\)/),10) + 1;
            newname = "Copy of [" + nCount[1] + "] " + oldname;
            $('#newfilename').val(newname); 
    }else{
        newname = "Copy of [1] " + oldname'
    }
    $('#newfilename').val(newname);

  }
});

Answer 1

我对您的代码进行了以下调整：

  if(oldname.substr(0, 7) == "Copy of"){
    var nCount = parseInt(oldname.match(/\[(\d+?)\]/)[1],10) + 1;
    var newname = oldname.replace(/\[\d+?\]/, "["+nCount+"]");
    $('#newfilename').val(newname);
  }
  else
  {
    $('#newfilename').val("Copy of [1] " + oldname); //prepend Copy of [1]
  }

看oldname.substr(0, 7) == "Copy of"前indexOf跳过if，而不执行代码。

现在[(\d+?)\]真有效。它会取出[和]之间的所有数字，并将它们归入()。 \d+?表示获取1或n次出现的所有数字。 ?将其lazy设为]。

var newname = oldname.replace(/\[\d+?\]/, "["+nCount+"]")只需对[]块进行替换，然后将其替换为nCount。

您甚至可以仅使用替换来优化它：

    var newname = oldname.replace(/\[(\d+?)\]/, function(whole, group1){
        return "[" + (parseInt(group1, 10)+1) + "]";
    });

$('#btnGenerate').click(function(){
	var oldname = $('#filename').val();
    if(typeof oldname !== undefined || oldname != ''){
      if(oldname.substr(0, 7) == "Copy of"){
        var newname = oldname.replace(/\[(\d+?)\]/, function(whole, group1){
        	return "[" + (parseInt(group1, 10)+1) + "]";
        });
        $('#newfilename').val(newname); 
      }
      else
      {
      	$('#newfilename').val("Copy of [1] " + oldname); //prepend Copy of [1]
      }     
  }
});

.panel{
  display:block;
  padding: 5px 10px;
}
.panel input{
  width:100%;
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="panel">
  <input type="text" id="filename" value="Copy of [1] filename">
</div>
<div class="panel">
  <input type="text" id="newfilename" value="">
</div>
<div class="panel">
  <button type="button" id="btnGenerate">
    Get File Name
  </button>
</div>

在一个完全不同的主题上。您正在构建一个文件系统类型的控件。复制金额是由该文件名（和副本）的出现次数决定的不是更好吗？

Answer 2

＆＃13;

import java.util.Scanner;

public class SimpleCalculator
{
   //-----------------------------------------------------------------
   //  Calculates two integers 
   //  using values entered by the user.
   //-----------------------------------------------------------------
    public static void main(String[] args) 
    {
        //Variables
        final int ADDITION = 1,SUBTRACTION = 2, MULTIPLICATION = 3,DIVISION = 4, EXIT = 5;
        int num1 = 0, num2 = 0, choice = 0;
        double dblNum1, dblNum2, result;
        String equation = "";

        do
        {
            //Processing
            equation = "";
            Scanner scan = new Scanner(System.in);
            System.out.println("Choose from the following: ");
            System.out.println("1. Add 2 integers");
            System.out.println("2. Subtract 2 integers");
            System.out.println("3. Multiply 2 integers");
            System.out.println("4. Divide 2 integers");
            System.out.println("5. Exit");
            System.out.print("Enter choice: ");

            choice = scan.nextInt();

                if(choice < 5 && choice > 0)//keeps program from asking for two numbers if exiting
                {
                    System.out.print("Enter first integer: ");
                    num1 = scan.nextInt();

                    System.out.print("Enter second integer: ");
                    num2 = scan.nextInt();
                }

            //switch for operations
            switch (choice)
            {
                case ADDITION:
                    result = num1 + num2;
                    equation = ((num1) + " + " + (num2) + " = "+ result);
                    break;

                case SUBTRACTION:
                    result = num1 - num2;
                    equation = ((num1) + " - " + (num2) + " = "+ result);
                    break;

                case MULTIPLICATION:
                    result = num1 * num2;
                    equation = ((num1) + " * " + (num2) + " = "+ result);
                    break;

                case DIVISION:
                    if(num2 == 0)//when denominator becomes zero
                    {
                        System.out.println("DIVISION NOT POSSIBLE");
                        break;
                    }
                    dblNum1 = num1;//convert int to double
                    dblNum2 = num2;
                    result = dblNum1/dblNum2;
                    equation = ((num1) + "/" + (num2) + " = "+ result);
                    break;

                case EXIT:
                    System.exit(0);
                    break;

                default:
                    System.out.println("YOU HAVE ENTERED AN INCORRECT CHOICE");             
            }
            //Output
            System.out.println(equation);
            System.out.println();
        }while(choice != EXIT);
    }
}

＆＃13;

names =  new Array()
$('#btnGenerate').click(function(){
	var oldname = $('#filename').val();
  names.push(oldname);
  if(oldname != ''){
    
var nCount  = $.grep(names, function (elem) {
    return elem === oldname;
}).length;
      var newname = "Copy of [" +nCount + "] " + oldname;
			$('#newfilename').val(newname);  
  }
 
});

＆＃13;

.panel{
  display:block;
  padding: 5px 10px;
}
.panel input{
  width:100%;
}

＆＃13;

我希望这就是你要找的东西。

Answer 3

<强> Updated fiddle

你是如此接近，你只是稍微调整正则表达式并添加其他语句：

$('#btnGenerate').click(function(){
  var oldname = $('#filename').val();
  if(typeof oldname !== undefined || oldname != ''){

    //Adding '>-1' in this condition
    if(oldname.indexOf('Copy of')>-1) 
    { 
      var nCount = parseInt(oldname.match(/\[(.*)\]/)[1],10) + 1;
      var file_name = oldname.split('] ')[1];

      var newname = "Copy of [" + nCount + "] " + file_name;
    }else{
      var newname = 'Copy of [1] '+oldname;
    }

    $('#newfilename').val(newname); 
  }
});

希望这有帮助。

＆＃13;

$('#btnGenerate').click(function(){
  var oldname = $('#filename').val();
  if(typeof oldname !== undefined || oldname != ''){
    if(oldname.indexOf('Copy of')>-1){
      var nCount = parseInt(oldname.match(/\[(.*)\]/)[1],10) + 1;
      var file_name = oldname.split('] ')[1];

      var newname = "Copy of [" + nCount + "] " + file_name;
    }else{
      var newname = 'Copy of [1] '+oldname;
    }

    $('#newfilename').val(newname); 
  }
});

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="panel">
  <input type="text" id="filename" value="Copy of [1] filename">
</div>
<div class="panel">
  <input type="text" id="newfilename" value="">
</div>
<div class="panel">
  <button type="button" id="btnGenerate">
    Get File Name
  </button>
</div>

＆＃13;

Answer 4

您的代码正常运行，但您必须从

更改正则表达式

 /\([.*]\)/ to /\d+/

生成文本取决于另一个文本框值

4 个答案: