我试图将记录的名称发送到我的模态并回显| async
及其constructor(private _cocktailService: CocktailService) {
this.cocktails = _cocktailService.getCocktails().map(
res => this.cocktails = res
);
}
,但我继续只获取最后一条记录。
以下是我的代码:
declare @StartDate DATE = '2016-11-19';
declare @EndDate DATE = '2016-11-29';
--SET DATEFIRST 7;
-- The dw for tuesday is 3 when @@datefirst = 7 (default setting)
-- Since it depends on a usersetting, lets calculate it anyway.
declare @TuesdayWeekday INT = (7-@@datefirst + 2)%7+1;
;with DATES as
(
select @startdate as [Date]
union all
select dateadd(day, 1, [Date]) from DATES
where [Date] < @enddate
)
select [Date], datepart(dw,[Date]) as day_of_week, datename(dw,[Date]) as day_of_weekname
from DATES
where datepart(dw,[Date]) = @TuesdayWeekday;
这是我的模态的代码:
name
我的表格示例中有三个数据:
食品 书 睡眠
当我点击食物旁边的按钮时,我的模态中的数据将是睡眠。
我希望有人会帮助我。谢谢